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Water - Jessica #51
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Water - Jessica #51
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# Calculates the length of the restricted array. All values are integers. | ||
# The restricted_array is terminated by 'nil' i.e. array[length] = nil | ||
# Time complexity: ? | ||
# Space complexity: ? | ||
# Time complexity: O(n) | ||
# Space complexity: O(1) | ||
#[2,3,6,8,1,3] | ||
def length(array) | ||
raise NotImplementedError | ||
i = 0 | ||
until array[i] == nil | ||
i += 1 | ||
end | ||
return i | ||
end | ||
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# Prints each integer values in the array | ||
# Time complexity: ? | ||
# Space complexity: ? | ||
# Time complexity: O(n) | ||
# Space complexity: O(1) | ||
def print_array(array) | ||
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raise NotImplementedError | ||
i = 0 | ||
until array[i] == nil | ||
puts array[i] | ||
i += 1 | ||
end | ||
end | ||
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# For an unsorted array, searches for 'value_to_find'. | ||
# Returns true if found, false otherwise. | ||
# Time complexity: ? | ||
# Space complexity: ? | ||
# Time complexity: O(n) | ||
# Space complexity: O(1) | ||
def search(array, length, value_to_find) | ||
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raise NotImplementedError | ||
i = 0 | ||
while i < length | ||
if array[i] == value_to_find | ||
return true | ||
end | ||
i += 1 | ||
end | ||
return false | ||
end | ||
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# Finds and returns the largest integer value the array | ||
# Finds and returns the largest integer value in the array | ||
# Assumes that the array is not sorted. | ||
# Time complexity: ? | ||
# Space complexity: ? | ||
# Time complexity: O(n) | ||
# Space complexity: O(1) | ||
def find_largest(array, length) | ||
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raise NotImplementedError | ||
i = 0 | ||
largest_value = 0 | ||
until i == length | ||
if array[i] > largest_value | ||
largest_value = array[i] | ||
end | ||
i += 1 | ||
end | ||
return largest_value | ||
end | ||
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# Finds and returns the smallest integer value in the array | ||
# Assumes that the array is not sorted. | ||
# Time complexity: ? | ||
# Space complexity: ? | ||
# Time complexity: O(n) | ||
# Space complexity: O(1) | ||
def find_smallest(array, length) | ||
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raise NotImplementedError | ||
i = 0 | ||
smallest_value = array[0] | ||
until i == length | ||
if array[i] < smallest_value | ||
smallest_value = array[i] | ||
end | ||
i += 1 | ||
end | ||
return smallest_value | ||
end | ||
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# Reverses the values in the integer array in place | ||
# Time complexity: ? | ||
# Space complexity: ? | ||
# Time complexity: O(n) | ||
# Space complexity: O(1) | ||
def reverse(array, length) | ||
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raise NotImplementedError | ||
i = length - 1 | ||
j = 0 | ||
temp_value = 0 | ||
until i < j | ||
temp_value = array[i] | ||
array[i] = array[j] | ||
array[j] = temp_value | ||
i -= 1 | ||
j += 1 | ||
end | ||
return array | ||
end | ||
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# For an array sorted in ascending order, searches for 'value_to_find'. | ||
# Returns true if found, false otherwise. | ||
# Time complexity: ? | ||
# Space complexity: ? | ||
# Time complexity: O(log n) | ||
# Space complexity: O(1) | ||
# [1,3,6,7,9,13,17,22], 8, 22 | ||
# [1,2] | ||
def binary_search(array, length, value_to_find) | ||
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raise NotImplementedError | ||
min = 0 | ||
max = length-1 | ||
until min == max | ||
mid = (min + max)/2 | ||
if value_to_find > array[mid] | ||
min = mid + 1 | ||
elsif value_to_find < array[mid] | ||
max = mid - 1 | ||
else | ||
return true | ||
end | ||
end | ||
if array[min] == value_to_find | ||
return true | ||
end | ||
return false | ||
end | ||
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# Helper method provided to sort the array in ascending order | ||
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