Handling derived classes more elegant

[ramondeklein]

Assume I have the following class structure and I want to be able to map between the two:

public class Base1
public class DerivedA1 : Base1
public class DerivedB1 : Base1

public class Base2
public class DerivedA2 : Base2
public class DerivedB2 : Base2

I have to create two functions to map between the two:

static Base2 Map1to2(Base1 base1)
{
    if (base1 is DerivedA1)
        return ((DerivedA1)base1).Adapt<DerivedA2>();
    if (base1 is DerivedB1)
        return ((DerivedB1)base1).Adapt<DerivedB2>();
    return base1.Adapt<Base2>();
}

static Base1 Map2to1(Base2 base2)
{
    if (base2 is DerivedA2)
        return ((DerivedA2)base2).Adapt<DerivedA1>();
    if (base2 is DerivedB2)
        return ((DerivedB2)base2).Adapt<DerivedB1>();
    return base2.Adapt<Base1>();
}

And I need to setup these mappers:

var config = new TypeAdapterConfig();
config.ForType<Base1, Base2>().ConstructUsing(src => Map1to2(src));
config.ForType<Base2, Base1>().ConstructUsing(src => Map2to1(src));
var adapter = new Adapter(config);

Using this approach I can use adapter.Adapt<Base2>(derivedB1) and still get an instance of DerivedB2.

It would be much more elegant that we don't require such additional methods, but to use the same kind of syntax that AutoMapper is using:

config.ForType<Base1, Base2>().Include<DerivedA1, DerivedA2>().Include<DerivedB1, DerivedB2>();
config.ForType<Base2, Base1>().Include<DerivedA2, DerivedA1>().Include<DerivedB2, DerivedB1>();

I have found the Inherits method, but it doesn't seem to work for this scenario.

[chaowlert]

Hi, I added Include command in Mapster 3.0 (https://github.com/chaowlert/Mapster/wiki/Config-inheritance), please try. Thx u.