diff --git a/change_notes/2023-07-11-lambda-expr-without-param-list.md b/change_notes/2023-07-11-lambda-expr-without-param-list.md
new file mode 100644
index 0000000000..4a5b4cf5ad
--- /dev/null
+++ b/change_notes/2023-07-11-lambda-expr-without-param-list.md
@@ -0,0 +1 @@
+ - Only consider lambdas that have zero arguments, since any lambda with non-zero arguments will have an explicit argument list. 
diff --git a/cpp/autosar/src/rules/A5-1-3/LambdaExpressionWithoutParameterList.ql b/cpp/autosar/src/rules/A5-1-3/LambdaExpressionWithoutParameterList.ql
index 4583f8675e..db39a62d8e 100644
--- a/cpp/autosar/src/rules/A5-1-3/LambdaExpressionWithoutParameterList.ql
+++ b/cpp/autosar/src/rules/A5-1-3/LambdaExpressionWithoutParameterList.ql
@@ -21,6 +21,10 @@ where
   not isExcluded(lambda, LambdasPackage::lambdaExpressionWithoutParameterListQuery()) and
   lambdaFunction = lambda.getLambdaFunction() and
   not lambdaFunction.isAffectedByMacro() and
+  // If it has a parameter, then it will have an
+  // explicit parameter list. Therefore, proceed to check only if the lambda
+  // does not have any parameters.
+  not exists (lambdaFunction.getAParameter()) and
   // The extractor doesn't store the syntactic information whether the parameter list
   // is enclosed in parenthesis. Therefore we cannot determine if the parameter list is
   // explicitly specified when the parameter list is empty.