fix: Create copy of backoff struct #598
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The backoff is created in `interceptor/main.go` and `.Step()` is a pointer receiver, so `.Step()` will mutate the underling number of `.Steps` within the struct. When you have 0 replicas, the default 500ms timeout of the Dial is hit which basically guarantees that you will end up calling `.Step()`. The value inside the the struct will never be reset, and so every single time you're scaling from 0, you're guaranteed to reduce the number of `.Steps` by 1 and this will never reset until the application itself has been restarted. This change makes sure that every time we execute `DialContextWithRetry`, we start with a fresh `backoff` which will start the `.Steps` at 5 since it's a clone of the original `backoff`. This `backoff` is available in the context of the function returned by `DialContextWithRetry`, which will be the one that gets decremented, and then will be garbage collected and we get a brand new 5 steps the next time we execute `DialContextWithRetry`. Closes kedacore#586 Signed-off-by: Aaron Batilo <AaronBatilo@gmail.com>
JorTurFer
approved these changes
Feb 7, 2023
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The backoff is created in
interceptor/main.goand.Step()is a pointer receiver, so.Step()will mutate the underling number of.Stepswithin the struct. When you have 0 replicas, the default 500ms timeout of the Dial is hit which basically guarantees that you will end up calling.Step(). The value inside the the struct will never be reset, and so every single time you're scaling from 0, you're guaranteed to reduce the number of.Stepsby 1 and this will never reset until the application itself has been restarted.This change makes sure that every time we execute
DialContextWithRetry, we start with a freshbackoffwhich will start the.Stepsat 5 since it's a clone of the originalbackoff. Thisbackoffis available in the context of the function returned byDialContextWithRetry, which will be the one that gets decremented, and then will be garbage collected and we get a brand new 5 steps the next time we executeDialContextWithRetry.Fixes #586
Signed-off-by: Aaron Batilo AaronBatilo@gmail.com