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Faulty operator precedence parsing in haskell #341

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julian-berbel opened this issue Dec 15, 2021 · 1 comment

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julian-berbel commented Dec 15, 2021

The following piece of code:

foo = (even $ 5) || False

(valid)

Gets parsed to the same ast as:

foo = even $ 5 || False

(type error)

Member Author

julian-berbel commented Dec 15, 2021 •

edited

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This doesn't seem like an easy fix; the haskell parser is parsing the previous two pieces of code to this:

HsInfixApp 
  (HsParen (HsInfixApp (HsVar (UnQual (HsIdent "even"))) (HsQVarOp (UnQual (HsSymbol "$"))) (HsLit (HsInt 5))))
  (HsQVarOp (UnQual (HsSymbol "||")))
  (HsCon (UnQual (HsIdent "False")))

HsInfixApp 
  (HsInfixApp (HsVar (UnQual (HsIdent "even"))) (HsQVarOp (UnQual (HsSymbol "$"))) (HsLit (HsInt 5)))
  (HsQVarOp (UnQual (HsSymbol "||")))
  (HsCon (UnQual (HsIdent "False")))

The resulting tree hierarchy does not to reflect the operator precedence, it seems that is accounted for at a later stage.

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