Only return -1 in get_indexer for incorrect values

Instead of returning [-1, -1, -1] when the middle value is incorrect
type, return [a, -1, b].

Author: samuelsinayoko

pandas/core/indexes/interval.py

@@ -833,12 +833,11 @@ def get_indexer(self, target, method=None, limit=None, tolerance=None):
                 start, stop = (
                     self._find_non_overlapping_monotonic_bounds(target)
                 )
+                start_plus_one = start + 1
+                if not ((start_plus_one < stop).any()):
+                    return np.where(start_plus_one == stop, start, -1)
             except TypeError:
-                return np.repeat(np.int(-1), len(target))
-
-            start_plus_one = start + 1
-            if not ((start_plus_one < stop).any()):
-                return np.where(start_plus_one == stop, start, -1)
+                pass
 
         if not self.is_unique:
             raise ValueError("cannot handle non-unique indices")
@@ -854,8 +853,8 @@ def get_indexer(self, target, method=None, limit=None, tolerance=None):
                 try:
                     vals.append(self.get_loc(i))
                 except KeyError:
-                    vals.append(np.array([-1]))
-                indexer = np.concatenate(vals)
+                    vals.append(-1)
+            indexer = np.array(vals)
 
         return ensure_platform_int(indexer)
 

pandas/tests/indexes/interval/test_interval.py

@@ -591,6 +591,14 @@ def test_get_indexer(self):
         expected = np.array([-1, 1], dtype='intp')
         tm.assert_numpy_array_equal(actual, expected)
 
+        actual = self.index.get_indexer(['a', 1])
+        expected = np.array([-1, 0], dtype='intp')
+        tm.assert_numpy_array_equal(actual, expected)
+
+        actual = self.index.get_indexer(['a', 1, 'b'])
+        expected = np.array([-1, 0, -1], dtype='intp')
+        tm.assert_numpy_array_equal(actual, expected)
+
     # To be removed, replaced by test_interval_new.py (see #16316, #16386)
     def test_get_indexer_subintervals(self):