IPv4-mapped IPv6 addresses cause 'ClassCastException' #73
Comments
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Yes, it seems InetAddress.getByAddress returns an Inet4Address for IPv4-mapped IPv6 addresses. So this is a bug in IPAddress which will be fixed in all future releases. In the meantime, here are a couple of work-arounds. They both do the same thing. The first is a little more explicit about what is going on, and the second is shorter. public static void main(String[] args) throws HostNameException, UnknownHostException {
IPAddress address = new HostName("[::FFFF:192.168.8.165]").toAddress();
try {
error(address);
} catch(ClassCastException e) {
System.out.println("oops! " + e);
}
System.out.println(workaroundOne(address));
System.out.println(workaroundTwo(address));
}
public static void error(IPAddress address) throws HostNameException, UnknownHostException {
address.toInetAddress();
}Option 1 public static InetAddress workaroundOne(IPAddress address) {
if(address.isIPv6()) {
IPv6Address addr = address.toIPv6();
if(addr.isIPv4Mapped()) {
address = addr.toIPv4();
}
}
return address.toInetAddress();
}Option 2 public static InetAddress workaroundTwo(IPAddress address) {
if(address.isIPv4Convertible()) {
address = address.toIPv4();
}
return address.toInetAddress();
}Output: |
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Thank you for quick response, I've find another workaround.
this works fine |
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This has been fixed in the newly released version 5.3.4 |
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Hi,
I'm having a problems with IPv4-mapped IPv6 addresses. Code below throws ClassCastException.
`java.lang.ClassCastException: class java.net.Inet4Address cannot be cast to class java.net.Inet6Address (java.net.Inet4Address and java.net.Inet6Address are in module java.base of loader 'bootstrap')
`
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