Difficulty: Easy
https://leetcode.com/problems/convert-sorted-array-to-binary-search-tree/
The code is shown below:
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def sortedArrayToBST(self, nums: List[int]) -> Optional[TreeNode]:
if not nums:
return None
def buildTree(nums, start, end):
if start > end:
return None
elif start == end:
return TreeNode(nums[start])
else:
mid = (start + end) // 2
cur_node = TreeNode(nums[mid])
cur_node.left = buildTree(nums, start, mid-1)
cur_node.right = buildTree(nums, mid+1, end)
return cur_node
return buildTree(nums, 0, len(nums)-1)