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Is it possible to delaunayquad from the given triangulation? #1
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Thanks, @TangLaoya, for your interest! The code runs 5 steps:
So, I think coloring the vertices is already separated from triangulation. If you already have a triangle mesh (must be Delaunay mesh from random pointset), all you need to do is to color the vertices of this triangle mesh randomly (and implement the heuristics in Step 3) and then you can go to Step 4 directly. Hope this answers your questions! |
Dear Prof. Ahdhn, void DeaunayQuad(int nnode, double node, int ntri, int tri, int &nquad, int quad); Thanks, PS: I also attached a delaunay mesh, could you please help me to take a look at it? |
I am sorry but I don't have the time to spend on making changes to this code. The code is supposed to reproduce the results in the paper in which point set generation is a part of the algorithm. I am not sure why step takes "very long time to execute". It is possible to integrate step 3 while assigning the colors randomly. |
Dear Prof. Ahdhn,
Thank you very much for providing so powerful 'DelaunayQuad', from your result it is quick and generated high quality quads. However, I noticed that you colored vertices along with the triangulation, could you please separate these steps, i.e., could you please give me an example to generate quad mesh from a given triangulation?
Thanks,
Tang Laoya
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