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feat: 153. Find Minimum in Rotated Sorted Array
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// Time complexity: O(logn)
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// Space complexity: O(1)
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/**
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* @param {number[]} nums
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* @return {number}
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*/
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var findMin = function (nums) {
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let left = 0;
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let right = nums.length - 1;
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while (left < right) {
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const mid = Math.floor((left + right) / 2);
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if (nums.at(mid - 1) > nums.at(mid)) {
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return nums[mid];
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}
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if (nums.at(mid + 1) < nums.at(mid)) {
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return nums[mid + 1];
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}
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if (nums.at(mid + 1) > nums.at(right)) {
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left = mid + 1;
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continue;
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}
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right = mid - 1;
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}
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return nums[left];
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};

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