Merge pull request #1362 from jinhyungrhee/week4

[jinhyungrhee] Week 04 Solutions

Author: jinhyungrhee

coin-change/jinhyungrhee.java

@@ -0,0 +1,22 @@
+import java.util.*;
+class Solution {
+    int INF = 987654321;
+    public int coinChange(int[] coins, int amount) {
+        if (amount == 0) return 0;
+
+        int[] dp = new int[amount + 1];
+        Arrays.fill(dp, INF);
+
+        dp[0] = 0;
+        for (int coin : coins) {
+            if (coin <= amount) dp[coin] = 1;
+        }
+
+        for (int i = 1; i <= amount; i++) {
+            for (int coin : coins) {
+                if ((i - coin) >= 0) dp[i] = Math.min(dp[i], dp[i - coin] + 1);
+            }
+        }
+        return (dp[amount] == INF) ? -1 : dp[amount];
+    }
+}

find-minimum-in-rotated-sorted-array/jinhyungrhee.java

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+class Solution {
+    public int findMin(int[] nums) {
+        int left = 0, right = nums.length - 1;
+        // 오름차순인 경우 
+        if (nums[left] < nums[right]) return nums[left];
+        // 오름차순이 아닌 경우 이진탐색
+        while (left < right) {
+            int mid = (left + right) / 2;
+            if (nums[mid] < nums[right]) {
+                right = mid;
+            } else {
+                left = mid + 1;
+            }
+        }
+        return nums[left];
+    }
+}

maximum-depth-of-binary-tree/jinhyungrhee.java

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+class Solution {
+    public int maxVal;
+    public int maxDepth(TreeNode root) {
+        dfs(root, 0);
+        return maxVal;
+    }
+    public void dfs(TreeNode node, int step) {
+
+        if (node == null) {
+            if (maxVal < step) maxVal = step;
+            return;
+        }
+
+        dfs(node.left, step + 1);
+        dfs(node.right, step + 1);
+    }
+}

merge-two-sorted-lists/jinhyungrhee.java

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+class Solution {
+    public ListNode mergeTwoLists(ListNode list1, ListNode list2) {
+
+        ListNode dummy = new ListNode(0);
+        ListNode current = dummy; // ***실제로 노드를 이어나갈 포인터***
+
+        while (list1 != null && list2 != null) {
+            if (list1.val < list2.val) {
+                current.next = list1;
+                list1 = list1.next;
+            }
+            else {
+                current.next = list2;
+                list2 = list2.next;
+            }
+            current = current.next;
+        }
+
+        // 남아있는 노드들 이어붙이기
+        if (list1 != null) {
+            current.next = list1;
+        }
+        if (list2 != null) {
+            current.next = list2;
+        }
+
+        return dummy.next;
+    }
+}

word-search/jinhyungrhee.java

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+class Solution {
+    public boolean exist(char[][] board, String word) {
+
+        boolean[][] visited = new boolean[board.length][board[0].length];
+
+        for (int i = 0; i < board.length; i++) {
+            for (int j = 0; j < board[0].length; j++) {
+                if(dfs(board, word, visited, i, j, 0)) {
+                    return true;
+                }
+            }
+        }
+        return false;
+    }
+
+    public boolean dfs(char[][] board, String word, boolean[][] visited, int x, int y, int index) {
+
+        // [성공] : 모든 글자 매칭 성공
+        if (index == word.length()) return true;
+
+        // [실패] : 범위 초과, 방문함, 글자 불일치
+        if (x < 0 || x >= board.length || y < 0 || y >= board[0].length ||
+                visited[x][y] || board[x][y] != word.charAt(index)) {
+            return false;
+        }
+
+        visited[x][y] = true;
+        int[][] dir = {{1, 0}, {-1, 0}, {0, -1}, {0, 1}};
+        for (int i = 0; i < 4; i++) {
+            int newX = x + dir[i][0], newY = y + dir[i][1];
+            if (dfs(board, word, visited, newX, newY, index + 1)) {
+                return true; // 찾았으면 바로 리턴
+            }
+        }
+        visited[x][y] = false; // backtrack
+
+        return false; // 4방향 다 실패하면 false
+
+    }
+}