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solve
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/**
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* Definition for a binary tree node.
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* public class TreeNode {
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* public var val: Int
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* public var left: TreeNode?
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* public var right: TreeNode?
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* public init() { self.val = 0; self.left = nil; self.right = nil; }
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* public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }
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* public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {
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* self.val = val
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* self.left = left
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* self.right = right
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* }
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* }
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*/
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class Solution {
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// O(n * m) time / O(n) space
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func isSubtree(_ root: TreeNode?, _ subRoot: TreeNode?) -> Bool {
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let subRootNode = subRoot?.val
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var queue = [TreeNode]()
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guard let root = root else {
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return false
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}
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queue.append(root)
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var head = 0
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while queue.count > head {
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let currentNode = queue[head]
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head += 1
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if currentNode.val == subRootNode {
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if dfs(node: currentNode, subRoot: subRoot) {
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return true
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}
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}
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if let left = currentNode.left {
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queue.append(left)
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}
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if let right = currentNode.right {
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queue.append(right)
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}
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}
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return false
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}
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func dfs(node: TreeNode?, subRoot: TreeNode?) -> Bool {
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guard let node = node, let subRoot = subRoot else {
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return node == nil && subRoot == nil
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}
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return node.val == subRoot.val
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&& dfs(node: node.left, subRoot: subRoot.left)
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&& dfs(node: node.right, subRoot: subRoot.right)
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}
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}

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