| 
 | 1 | +/**  | 
 | 2 | + * Definition for a binary tree node.  | 
 | 3 | + * public class TreeNode {  | 
 | 4 | + *     public var val: Int  | 
 | 5 | + *     public var left: TreeNode?  | 
 | 6 | + *     public var right: TreeNode?  | 
 | 7 | + *     public init() { self.val = 0; self.left = nil; self.right = nil; }  | 
 | 8 | + *     public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }  | 
 | 9 | + *     public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {  | 
 | 10 | + *         self.val = val  | 
 | 11 | + *         self.left = left  | 
 | 12 | + *         self.right = right  | 
 | 13 | + *     }  | 
 | 14 | + * }  | 
 | 15 | + */  | 
 | 16 | +class Solution {  | 
 | 17 | +    // O(n * m) time / O(n) space  | 
 | 18 | +    func isSubtree(_ root: TreeNode?, _ subRoot: TreeNode?) -> Bool {  | 
 | 19 | +        let subRootNode = subRoot?.val  | 
 | 20 | + | 
 | 21 | +        var queue = [TreeNode]()  | 
 | 22 | +        guard let root = root else {  | 
 | 23 | +            return false  | 
 | 24 | +        }  | 
 | 25 | +        queue.append(root)  | 
 | 26 | +        var head = 0  | 
 | 27 | +        while queue.count > head {  | 
 | 28 | +            let currentNode = queue[head]  | 
 | 29 | +            head += 1  | 
 | 30 | +            if currentNode.val == subRootNode {  | 
 | 31 | +                if dfs(node: currentNode, subRoot: subRoot) {  | 
 | 32 | +                    return true  | 
 | 33 | +                }  | 
 | 34 | +            }  | 
 | 35 | +              | 
 | 36 | +            if let left = currentNode.left {  | 
 | 37 | +                queue.append(left)  | 
 | 38 | +            }  | 
 | 39 | +            if let right = currentNode.right {  | 
 | 40 | +                queue.append(right)  | 
 | 41 | +            }  | 
 | 42 | +        }  | 
 | 43 | + | 
 | 44 | +        return false  | 
 | 45 | +    }  | 
 | 46 | + | 
 | 47 | +    func dfs(node: TreeNode?, subRoot: TreeNode?) -> Bool {  | 
 | 48 | +        guard let node = node, let subRoot = subRoot else {  | 
 | 49 | +            return node == nil && subRoot == nil  | 
 | 50 | +        }  | 
 | 51 | + | 
 | 52 | +        return node.val == subRoot.val  | 
 | 53 | +        && dfs(node: node.left, subRoot: subRoot.left)  | 
 | 54 | +        && dfs(node: node.right, subRoot: subRoot.right)  | 
 | 55 | +    }  | 
 | 56 | + | 
 | 57 | +}  | 
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