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feat: 문제풀이 추가
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maximum-subarray/hwanmini.js

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// 시간복잡도: O(n)
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// 공간복잡도: O(1)
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/**
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* @param {number[]} nums
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* @return {number}
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*/
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var maxSubArray = function (nums) {
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let maxNum = -Infinity;
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let prevSum = -Infinity;
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for (let i = 0 ; i < nums.length; i++) {
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prevSum = Math.max(prevSum + nums[i], nums[i])
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maxNum = Math.max(prevSum, maxNum)
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}
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return maxNum
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};

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