Code Block Conditional Statement returns wrong value

[paoloemilioserra]

If this issue is not a bug report or improvement request, please check the Dynamo forum, and start a thread there to discuss your issue.

Dynamo version

1.2.0.2690

Revit version

2017.1

Operating system

Windows 7

What did you do?

I'm using a conditional statement in a code block, when the input "a" is greater than 3 it should return a list of the inner elements, otherwise a list containing only the second item. Here is the formula.
output = Count(a) > 3 ? a[1..Count(a) - 2] : {a[1]};

What did you expect to see?

let's a = {0, 1, 2, 3} -> output = {1, 2}
let's a = {0, 1, 2} -> output = {1}

What did you see instead?

The above formula always return the false member. If I remove the curly brackets from the false member if works properly but I need a list of 1 item and not just the item

[andydandy74]

It's a feature. :-D Really.
Try this:

result[0] = a[1..Count(a) - 2];
result[1] = {a[1]};
result[Count(a) > 3 ? 0 : 1];

This has been discusssed here:
DynamoDS/Dynamo#6491
And here:
DynamoDS/Dynamo#6258
And here:
DynamoDS/Dynamo#4464
And here:
DynamoDS/Dynamo#3106

[paoloemilioserra]

Thanks! I still think that it should return a list as a variable type though

[andydandy74]

You're not alone with that sentiment.