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Reduce Independent Set Problem to Set Packing Problem
I. Definitions and Background
I-A. Independent Set Problem (IS)
See "Reduce 3-SAT to Independent SAT Problem" issue.
I-B. Set Packing Problem
Pairwise Disjoint: For a collection of sets, any two of them don't share elements.
Input:
An universe $U$ (need to check: whether $U$ needs to be a finite set);
A collection of $U$'s subsests: $S={S_1, S_2, \cdots S_m }$ (aka: family);
A collection of some of the above subsets (aka: subfamily) that is pairwise disjoint. This subfamily is called a packing, while the size of the packing is the number of subsets included.
Output:
Whether there is a packing of size $k$.
II. Proof (IS <= Set Packing)
The reduction is as follows [Ref. 1]:
Given an undirected graph $G=(V,E)$ and $k$, we aim to generate $(U, S, k)$.
Step-0: $k$ are the same;
Step-1: Each edge $(u,v)\in E$ -> Create an element $x_{u,v}$ in $U$;
Step-2: Each vertex $v \in V$ -> Create a subset ${S_{u,v}|(u,v)\in E }$.
It can be proven that:
$(G,k)$ is an yes-instance if and only if generated $(U,S,k)$ is an yes-instance;
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