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SpiralMatrixII.py
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SpiralMatrixII.py
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"""
Given a positive integer n, generate a square matrix filled with elements from 1 to n2 in spiral order.
Example:
Input: 3
Output:
[
[ 1, 2, 3 ],
[ 8, 9, 4 ],
[ 7, 6, 5 ]
]
想清楚在写。
beat 94%
测试地址:
https://leetcode.com/problems/spiral-matrix-ii/description/
"""
class Solution(object):
def generateMatrix(self, n):
"""
:type n: int
:rtype: List[List[int]]
"""
maps = [[0 for i in range(n)] for j in range(n)]
current_value = [i for i in range(1, n*n+1)]
current_value.reverse()
def makeXY(x, y):
# up
# down
# right
# left
return [(x, y-1),
(x, y+1),
(x+1, y),
(x-1, y)]
def right(x, y):
while 1:
if not current_value:
return maps
xy = makeXY(x, y)
if (y > -1 and x > -1) and (y < n and x < n):
if maps[y][x] == 0:
maps[y][x] = current_value.pop()
y, x = xy[2][1], xy[2][0]
else:
# down
return down(x-1, y+1)
else:
# down
return down(x-1, y+1)
def down(x, y):
while 1:
if not current_value:
return maps
xy = makeXY(x, y)
if (y > -1 and x > -1) and (y < n and x < n):
if maps[y][x] == 0:
maps[y][x] = current_value.pop()
y, x = xy[1][1], xy[1][0]
else:
# left
return left(x-1, y-1)
else:
# left
return left(x-1, y-1)
def left(x, y):
while 1:
if not current_value:
return maps
xy = makeXY(x, y)
if y > -1 and x > -1 and y < n and x < n:
if maps[y][x] == 0:
maps[y][x] = current_value.pop()
y, x = xy[3][1], xy[3][0]
else:
# up
return up(x+1, y-1)
else:
# up
return up(x+1, y-1)
def up(x, y):
while 1:
if not current_value:
return maps
xy = makeXY(x, y)
if y > -1 and x > -1 and y < n and x < n:
if maps[y][x] == 0:
maps[y][x] = current_value.pop()
y, x = xy[0][1], xy[0][0]
else:
# right
return right(x+1, y+1)
else:
# right
return right(x+1, y+1)
return right(0, 0)