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378.kth-smallest-element-in-a-sorted-matrix.104228393.ac.cpp
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378.kth-smallest-element-in-a-sorted-matrix.104228393.ac.cpp
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/*
* [378] Kth Smallest Element in a Sorted Matrix
*
* https://leetcode.com/problems/kth-smallest-element-in-a-sorted-matrix
*
* Medium (44.28%)
* Total Accepted:
* Total Submissions:
* Testcase Example: '[[1,5,9],[10,11,13],[12,13,15]]\n8'
*
* Given a n x n matrix where each of the rows and columns are sorted in
* ascending order, find the kth smallest element in the matrix.
*
*
* Note that it is the kth smallest element in the sorted order, not the kth
* distinct element.
*
*
* Example:
*
* matrix = [
* [ 1, 5, 9],
* [10, 11, 13],
* [12, 13, 15]
* ],
* k = 8,
*
* return 13.
*
*
*
* Note:
* You may assume k is always valid, 1 ≤ k ≤ n2.
*/
class Solution {
public:
int kthSmallest(vector<vector<int>>& matrix, int k) {
multimap<int, pair<int, int>> prio_queue =
{ {matrix[0][0], {0, 0}} };
for (int i = 1; i < k; i++)
{
auto iter = prio_queue.begin();
if (iter->second.first + 1 < matrix.size())
{
prio_queue.insert({
matrix[iter->second.first + 1][iter->second.second],
{iter->second.first + 1, iter->second.second}
});
matrix[iter->second.first + 1][iter->second.second] = INT_MAX;
}
if (iter->second.second + 1 < matrix.size())
{
prio_queue.insert({
matrix[iter->second.first][iter->second.second + 1],
{iter->second.first, iter->second.second + 1}
});
matrix[iter->second.first][iter->second.second + 1] = INT_MAX;
}
prio_queue.erase(iter);
}
return prio_queue.begin()->first;
}
};