using KDtree as a type?

[lobingera]

I've just seen the error the first time, i used (some time ago...) KDTree in a type definition

type pgraph
    x_screen::Array{Float64,1}
    y_screen::Array{Float64,1}
    x_last::Real
    y_last::Real
    kdtree::NearestNeighbors.KDTree{Float64,Distances.Euclidean}
end

which is later on instantiated with

p1 = pgraph(x,y,0.0,0.0,KDTree(zeros(2,2));

and p1.kdtree then given a value when applicable.

How to do that now?

[lobingera]

Don't mind, i'm using ::Any right now.

[KristofferC]

You could have

type pgraph{T <: KDTree}
    kdtree::T
end

[lobingera]

This was just an example, pgraph is actually a little bit longer than this and i might reserve the "top-level type argument" (don't know how {T <: X} is called...) for data, not the KDTree representation. The initial example worked for some time...

[KristofferC]

Yes, The new version (#29) changes the way the KDTree is parameterized. It is now a sufficiently complex type that I would recommand just adding an extra parameter that is T <: KDTree to your type.