practice-exercise-03-solution.ipynb

{
 "cells": [
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "# Practice Exercise - 03 - Solution"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### Question 1:\n",
    "\n",
    "Convert the string given below into a list by taking each word separated by a comma as an element.\n",
    "\n",
    "languages = \"Java, Python, C++, Scala, C\"\n",
    "\n",
    "#### Expected Output:\n",
    "\n",
    "['Java', ' Python', ' C++', ' Scala', ' C']"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 1,
   "metadata": {},
   "outputs": [
    {
     "data": {
      "text/plain": [
       "['Java', ' Python', ' C++', ' Scala', ' C']"
      ]
     },
     "execution_count": 1,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "languages = \"Java, Python, C++, Scala, C\"\n",
    "\n",
    "languages.split(',')"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### Question 2:\n",
    "\n",
    "We have a list of numbers given below. Add the element '10' at the 3rd position of the list and finally print the list.\n",
    "\n",
    "num_list = [5, 6, 8, 7, 9]\n",
    "\n",
    "#### Expected Output:\n",
    "\n",
    "[5, 6, 8, 10, 7, 9]"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 2,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[5, 6, 8, 10, 7, 9]\n"
     ]
    }
   ],
   "source": [
    "num_list = [5, 6, 8, 7, 9]\n",
    "\n",
    "num_list.insert(3, 10)\n",
    "\n",
    "print(num_list)"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### Question 3:\n",
    "\n",
    "Print all the multiples of 3 between 5 and 25.\n",
    "\n",
    "#### Expected Output:\n",
    "\n",
    "6\n",
    "<br>9\n",
    "<br>12\n",
    "<br>15\n",
    "<br>18\n",
    "<br>21\n",
    "<br>24"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 3,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "6\n",
      "9\n",
      "12\n",
      "15\n",
      "18\n",
      "21\n",
      "24\n"
     ]
    }
   ],
   "source": [
    "for i in range(5, 25):\n",
    "    if i % 3 == 0:\n",
    "        print(i)"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### Question 4:\n",
    "\n",
    "We have a list of numbers given below. Print the square of these numbers into another list using list comprehension.\n",
    "\n",
    "num = [2, 4, 6, 8]\n",
    "\n",
    "#### Expected Output:\n",
    "\n",
    "[4, 16, 36, 64]"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 4,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[4, 16, 36, 64]\n"
     ]
    }
   ],
   "source": [
    "num = [2, 4, 6, 8]\n",
    "\n",
    "square = [i**2 for i in num]\n",
    "\n",
    "print(square)"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### Question 5:\n",
    "\n",
    "Print the first 10 natural numbers.\n",
    "\n",
    "#### Expected Output:\n",
    "\n",
    "1\n",
    "<br>2\n",
    "<br>3\n",
    "<br>4\n",
    "<br>5\n",
    "<br>6\n",
    "<br>7\n",
    "<br>8\n",
    "<br>9\n",
    "<br>10"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 5,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "1\n",
      "2\n",
      "3\n",
      "4\n",
      "5\n",
      "6\n",
      "7\n",
      "8\n",
      "9\n",
      "10\n"
     ]
    }
   ],
   "source": [
    "num = 1\n",
    "\n",
    "while num <= 10:\n",
    "    print(num)\n",
    "    num += 1"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### Question 6:\n",
    "\n",
    "We have a tuple of numbers given below. Remove the largest number from the tuple and print it in sorted order.\n",
    "\n",
    "num_tuple = (5, 8, 13, 2, 17, 1)\n",
    "\n",
    "#### Expected Output:\n",
    "\n",
    "[1, 2, 5, 8, 13]"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 6,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[1, 2, 5, 8, 13]\n"
     ]
    }
   ],
   "source": [
    "num_tuple = (5, 8, 13, 2, 17, 1)\n",
    "\n",
    "sorted_num = sorted(num_tuple)\n",
    "sorted_num.pop()\n",
    "\n",
    "print(sorted_num)"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### Question 7:\n",
    "\n",
    "Convert the list given below into a string using a comma as a separator argument.\n",
    "\n",
    "myList = ['Lenovo', ' Dell', ' Acer', ' Asus', ' HP']\n",
    "\n",
    "#### Expected Output:\n",
    "\n",
    "'Lenovo, Dell, Acer, Asus, HP'"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 7,
   "metadata": {},
   "outputs": [
    {
     "data": {
      "text/plain": [
       "'Lenovo, Dell, Acer, Asus, HP'"
      ]
     },
     "execution_count": 7,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "myList = ['Lenovo', ' Dell', ' Acer', ' Asus', ' HP']\n",
    "\n",
    "myString = ','.join(myList)\n",
    "\n",
    "myString"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### Question 8:\n",
    "\n",
    "Print all the even numbers between -10 and 0.\n",
    "\n",
    "#### Expected Output:\n",
    "\n",
    "-10\n",
    "<br>-8\n",
    "<br>-6\n",
    "<br>-4\n",
    "<br>-2"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 8,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "-10\n",
      "-8\n",
      "-6\n",
      "-4\n",
      "-2\n"
     ]
    }
   ],
   "source": [
    "for i in range(-10, 0, 2):\n",
    "    print(i)"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### Question 9:\n",
    "\n",
    "Reverse the integer given below.\n",
    "\n",
    "n = 5623\n",
    "\n",
    "#### Expected Output:\n",
    "\n",
    "3265"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 9,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "3265\n"
     ]
    }
   ],
   "source": [
    "n = 5623\n",
    "rev = 0\n",
    "\n",
    "while n > 0:\n",
    "    rem = n % 10\n",
    "    rev = (rev * 10) + rem\n",
    "    n = n // 10\n",
    "    \n",
    "print(rev)"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### Question 10:\n",
    "\n",
    "We have a list of numbers given below. Print the number, square of the number, and the cube of the number, all in a single list.\n",
    "\n",
    "num = [2, 4, 6, 8]\n",
    "\n",
    "#### Expected Output:\n",
    "\n",
    "[(2, 4, 8), (4, 16, 64), (6, 36, 216), (8, 64, 512)]"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 10,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[(2, 4, 8), (4, 16, 64), (6, 36, 216), (8, 64, 512)]\n"
     ]
    }
   ],
   "source": [
    "num = [2, 4, 6, 8]\n",
    "\n",
    "result = [(x, x**2, x**3) for x in num]\n",
    "\n",
    "print(result)"
   ]
  }
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