practice-exercise-05-solution.ipynb

{
 "cells": [
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "# Practice Exercise - 05 - Solution"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### Question 1:\n",
    "\n",
    "Write a Python program to display the current date and time.\n",
    "\n",
    "#### Expected Output:\n",
    "\n",
    "Current date and time:  2020-10-17 16:02:50.583157"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 1,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "Current date and time:  2020-10-17 16:02:50.583157\n"
     ]
    }
   ],
   "source": [
    "from datetime import datetime\n",
    "\n",
    "print(\"Current date and time: \" , datetime.now())"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### Question 2:\n",
    "\n",
    "Print the month and minutes from the datetime object given below.\n",
    "\n",
    "dob_time = datetime(1995, 6, 14, 10, 37, 50, 0) \n",
    "\n",
    "#### Expected Output:\n",
    "\n",
    "Month: 6\n",
    "<br>Minutes: 37"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 2,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "Month: 6\n",
      "Minutes: 37\n"
     ]
    }
   ],
   "source": [
    "from datetime import datetime\n",
    "\n",
    "dob_time = datetime(1995, 6, 14, 10, 37, 50, 0) \n",
    "\n",
    "print('Month:', dob_time.month)\n",
    "print('Minutes:', dob_time.minute)"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### Question 3:\n",
    "\n",
    "Print the date in the format given below.\n",
    "\n",
    "Day_number  Month_name(abbr.)  Year - Day_name(abbr.)\n",
    "\n",
    "given_date = datetime(2011, 10, 12)\n",
    "\n",
    "#### Expected Output:\n",
    "\n",
    "12 Oct 2011 - Wed"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 3,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "12 Oct 2011 - Wed\n"
     ]
    }
   ],
   "source": [
    "from datetime import datetime\n",
    "\n",
    "given_date = datetime(2011, 10, 12)\n",
    "\n",
    "print(given_date.strftime('%d %b %Y - %a'))"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### Question 4:\n",
    "\n",
    "Write a Python program to find the day of the week of a given date?\n",
    "\n",
    "given_date = datetime(2008, 5, 15)\n",
    "\n",
    "#### Expected Output:\n",
    "\n",
    "Thursday"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 4,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "Thursday\n"
     ]
    }
   ],
   "source": [
    "from datetime import datetime\n",
    "\n",
    "given_date = datetime(2008, 5, 15)\n",
    "\n",
    "print(given_date.strftime('%A'))"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### Question 5:\n",
    "\n",
    "Write a Python program to add 2 days and 10 hours to a given date.\n",
    "\n",
    "given_date = datetime(2016, 2, 27, 11, 30, 0)\n",
    "\n",
    "#### Expected Output:\n",
    "\n",
    "2016-02-29 21:30:00"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 5,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "2016-02-29 21:30:00\n"
     ]
    }
   ],
   "source": [
    "from datetime import datetime, timedelta\n",
    "\n",
    "given_date = datetime(2016, 2, 27, 11, 30, 0)\n",
    "\n",
    "result = given_date + timedelta(days = 2, hours = 10)\n",
    "\n",
    "print(result)"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### Question 6:\n",
    "\n",
    "Write a Python program to calculate the number of days between two given dates.\n",
    "\n",
    "date_1 = datetime(2020, 7, 21).date()\n",
    "<br>date_2 = datetime(2020, 3, 10).date()\n",
    "\n",
    "#### Expected Output:\n",
    "\n",
    "133 days, 0:00:00"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 6,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "133 days, 0:00:00\n"
     ]
    }
   ],
   "source": [
    "from datetime import datetime\n",
    "\n",
    "date_1 = datetime(2020, 7, 21).date()\n",
    "date_2 = datetime(2020, 3, 10).date()\n",
    "\n",
    "print(date_1 - date_2)"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### Question 7:\n",
    "\n",
    "Write a Python program to convert a string to datetime.\n",
    "\n",
    "myString = Oct 12 2002 12:45 PM\n",
    "\n",
    "#### Expected Output:\n",
    "\n",
    "2002-10-12 12:45:00"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 7,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "2002-10-12 12:45:00\n"
     ]
    }
   ],
   "source": [
    "from datetime import datetime\n",
    "\n",
    "myString = 'Oct 12 2002 12:45 PM'\n",
    "    \n",
    "date_object = datetime.strptime(myString, '%b %d %Y %I:%M %p')\n",
    "print(date_object)"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### Question 8:\n",
    "\n",
    "Print the date, day name, and time in the format given below.\n",
    "\n",
    "Day_number-Month_number-Year - Day_name - Hours:Minutes:Seconds\n",
    "\n",
    "dob_time = datetime(1995, 6, 14, 10, 37, 50, 0) \n",
    "\n",
    "#### Expected Output:\n",
    "\n",
    "14-06-1995 - Wed - 10:37:50"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 8,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "14-06-1995 - Wednesday - 10:37:50\n"
     ]
    }
   ],
   "source": [
    "from datetime import datetime\n",
    "\n",
    "dob_time = datetime(1995, 6, 14, 10, 37, 50, 0) \n",
    "\n",
    "print(dob_time.strftime('%d-%m-%Y - %A - %H:%M:%S'))"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### Question 9:\n",
    "\n",
    "Write a Python program to print yesterdays' date.\n",
    "\n",
    "#### Expected Output:\n",
    "\n",
    "Yesterday :  2020-10-16"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 9,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "Yesterday :  2020-10-16\n"
     ]
    }
   ],
   "source": [
    "import datetime \n",
    "\n",
    "yesterday = datetime.date.today() - datetime.timedelta(days = 1)\n",
    "\n",
    "print('Yesterday : ',yesterday)"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### Question 10:\n",
    "\n",
    "Write a Python program to print the next 5 days from the date given below.\n",
    "\n",
    "given_date = datetime(2020, 10, 17)\n",
    "\n",
    "#### Expected Output:\n",
    "\n",
    "2020-10-18 00:00:00\n",
    "<br>2020-10-19 00:00:00\n",
    "<br>2020-10-20 00:00:00\n",
    "<br>2020-10-21 00:00:00\n",
    "<br>2020-10-22 00:00:00"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 10,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "2020-10-18 00:00:00\n",
      "2020-10-19 00:00:00\n",
      "2020-10-20 00:00:00\n",
      "2020-10-21 00:00:00\n",
      "2020-10-22 00:00:00\n"
     ]
    }
   ],
   "source": [
    "from datetime import datetime, timedelta\n",
    "\n",
    "given_date = datetime(2020, 10, 17)\n",
    "\n",
    "for x in range(1, 6):\n",
    "      print(given_date + timedelta(days=x))"
   ]
  }
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