-
Notifications
You must be signed in to change notification settings - Fork 0
/
Copy path226.翻转二叉树.py
52 lines (50 loc) · 1.06 KB
/
226.翻转二叉树.py
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
#
# @lc app=leetcode.cn id=226 lang=python3
#
# [226] 翻转二叉树
#
# https://leetcode-cn.com/problems/invert-binary-tree/description/
#
# algorithms
# Easy (67.79%)
# Total Accepted: 13.6K
# Total Submissions: 20K
# Testcase Example: '[4,2,7,1,3,6,9]'
#
# 翻转一棵二叉树。
#
# 示例:
#
# 输入:
#
# 4
# / \
# 2 7
# / \ / \
# 1 3 6 9
#
# 输出:
#
# 4
# / \
# 7 2
# / \ / \
# 9 6 3 1
#
# 备注:
# 这个问题是受到 Max Howell 的 原问题 启发的 :
#
# 谷歌:我们90%的工程师使用您编写的软件(Homebrew),但是您却无法在面试时在白板上写出翻转二叉树这道题,这太糟糕了。
#
#
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
def invertTree(self, root: TreeNode) -> TreeNode:
if root:
root.left, root.right = self.invertTree(root.right),self.invertTree(root.left)
return root