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Rollup merge of rust-lang#88690 - m-ou-se:macro-braces-dot-question-expr-parse, r=nagisa
Accept `m!{ .. }.method()` and `m!{ .. }?` statements.
This PR fixes something that I keep running into when using `quote!{}.into()` in a proc macro to convert the `proc_macro2::TokenStream` to a `proc_macro::TokenStream`:
Before:
```
error: expected expression, found `.`
--> src/lib.rs:6:6
|
4 | quote! {
5 | ...
6 | }.into()
| ^ expected expression
```
After:
```
```
(No output, compiles fine.)
---
Context:
For expressions like `{ 1 }` and `if true { 1 } else { 2 }`, we accept them as full statements without a trailing `;`, which means the following is not accepted:
```rust
{ 1 } - 1 // error
```
since that is parsed as two statements: `{ 1 }` and `-1`. Syntactically correct, but the type of `{ 1 }` should be `()` as there is no `;`.
However, for specifically `.` and `?` after the `}`, we do [continue parsing it as an expression](https://github.com/rust-lang/rust/blob/13db8440bbbe42870bc828d4ec3e965b38670277/compiler/rustc_parse/src/parser/expr.rs#L864-L876):
```rust
{ "abc" }.len(); // ok
```
For braced macro invocations, we do not do this:
```rust
vec![1, 2, 3].len(); // ok
vec!{1, 2, 3}.len(); // error
```
(It parses `vec!{1, 2, 3}` as a full statement, and then complains about `.len()` not being a valid expression.)
This PR changes this to also look for a `.` and `?` after a braced macro invocation. We can be sure the macro is an expression and not a full statement in those cases, since no statement can start with a `.` or `?`.
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