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接雨水 #19

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Mooo-star opened this issue Feb 26, 2024 · 1 comment
Open

接雨水 #19

Mooo-star opened this issue Feb 26, 2024 · 1 comment
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算法 记录算法

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@Mooo-star
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42. 接雨水

给定 n 个非负整数表示每个宽度为 1 的柱子的高度图,计算按此排列的柱子,下雨之后能接多少雨水。

示例 1:

输入:height = [0,1,0,2,1,0,1,3,2,1,2,1]
输出:6
解释:上面是由数组 [0,1,0,2,1,0,1,3,2,1,2,1] 表示的高度图,在这种情况下,可以接 6 个单位的雨水(蓝色部分表示雨水)。

示例 2:

输入:height = [4,2,0,3,2,5]
输出:9

提示:

  • n == height.length
  • 1 <= n <= 2 * 104
  • 0 <= height[i] <= 105
@Mooo-star Mooo-star added the 算法 记录算法 label Feb 26, 2024
@Mooo-star
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var trap = function (height) {
    const n = height.length;
    if (n == 0) {
        return 0;
    }

    const leftMax = new Array(n).fill(0);
    leftMax[0] = height[0];
    for (let i = 1; i < n; ++i) {
        leftMax[i] = Math.max(leftMax[i - 1], height[i]);
    }

    const rightMax = new Array(n).fill(0);
    rightMax[n - 1] = height[n - 1];
    for (let i = n - 2; i >= 0; --i) {
        rightMax[i] = Math.max(rightMax[i + 1], height[i]);
    }

    let ans = 0;
    for (let i = 0; i < n; ++i) {
        ans += Math.min(leftMax[i], rightMax[i]) - height[i];
    }
    return ans;
};

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