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给你一个整数数组 nums ,其中可能包含重复元素,请你返回该数组所有可能的 子集 (幂集)。
解集 不能 包含重复的子集。返回的解集中,子集可以按 任意顺序 排列。
示例 1:
输入:nums = [1,2,2] 输出:[[],[1],[1,2],[1,2,2],[2],[2,2]]
示例 2:
输入:nums = [0] 输出:[[],[0]]
The text was updated successfully, but these errors were encountered:
/** * @param {number[]} nums * @return {number[][]} */ var subsetsWithDup = function (nums) { const result = [] const len = nums.length const path = [] // 排序 nums.sort((a, b) => a - b) function backtack(startIndex) { result.push([...path]) for (let i = startIndex; i < len; i++) { if (i > startIndex && nums[i] === nums[i - 1]) continue path.push(nums[i]) backtack(i + 1) path.pop() } } backtack(0) return result };
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给你一个整数数组 nums ,其中可能包含重复元素,请你返回该数组所有可能的
子集
(幂集)。
解集 不能 包含重复的子集。返回的解集中,子集可以按 任意顺序 排列。
示例 1:
示例 2:
The text was updated successfully, but these errors were encountered: