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66. 机器人的运动范围.cpp
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66. 机器人的运动范围.cpp
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/*
地上有一个m行和n列的方格。一个机器人从坐标0,0的格子开始移动,
每一次只能向左,右,上,下四个方向移动一格,但是不能进入行坐标和列坐标的数位之和大于k的格子。
例如,当k为18时,机器人能够进入方格(35,37),因为3+5+3+7 = 18。
但是,它不能进入方格(35,38),因为3+5+3+8 = 19。请问该机器人能够达到多少个格子?
*/
/*
思路:回溯法
*/
class Solution {
public:
int movingCount(int threshold, int rows, int cols)
{
bool *visited = new bool[rows * cols]();
int count = movingCountCore(threshold, rows, cols, 0, 0, visited);
delete[] visited;
return count;
}
int movingCountCore(int threshold, int rows, int cols, int row, int col, bool *visited)
{
int count = 0;
if (check(threshold, rows, cols, row, col, visited))
{
visited[row * cols + col] = true;
count = 1 + movingCountCore(threshold, rows, cols, row, col - 1, visited)
+ movingCountCore(threshold, rows, cols, row - 1, col, visited)
+ movingCountCore(threshold, rows, cols, row, col + 1, visited)
+ movingCountCore(threshold, rows, cols, row + 1, col, visited);
}
return count;
}
bool check(int threshold, int rows, int cols, int row, int col, bool *visited)
{
if (row >= 0 && row < rows && col >= 0 && col < cols && !visited[row * cols + col] && getDigitSum(row) + getDigitSum(col) <= threshold)
return true;
else
return false;
}
int getDigitSum(int number)
{
int sum = 0;
while (number > 0)
{
sum += number % 10;
number /= 10;
}
return sum;
}
};