101-natural.c

#include <stdio.h>
/**
*main - prints count of multiples
*of 3 or 5 below 1024
*Return: return 0
*/
int main(void)
{
int n, sum = 0;
for (n = 0; n < 1024; n++)
{
if ((n % 3) == 0 || (n % 5) == 0)
sum += n;
}
printf("%d\n", sum);
return (0);
}