Given a binary tree, find the length of the longest path where each node in the path has the same value. This path may or may not pass through the root.
Note: The length of path between two nodes is represented by the number of edges between them.
Example 1:
Input:
5
/ \
4 5
/ \ \
1 1 5
Output:
2
Example 2:
Input:
1
/ \
4 5
/ \ \
4 4 5
Output:
2
Note: The given binary tree has not more than 10000 nodes. The height of the tree is not more than 1000.
- Method 1: Divide and conquer(Recursion).
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ class Solution { private int result; public int longestUnivaluePath(TreeNode root) { if(root == null) return 0; getPath(root); return this.result - 1; } private int getPath(TreeNode node){ if(node == null) return 0; int left = getPath(node.left); int right = getPath(node.right); int res = 1 + ((node.left == null || node.left.val == node.val) ? left: 0) + ((node.right == null || node.right.val == node.val) ? right: 0); this.result = Math.max(result, res); return Math.max((node.left == null || node.left.val == node.val) ? left: 0, (node.right == null || node.right.val == node.val) ? right: 0) + 1; } }