Skip to content
New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

LeetCode 70. Climbing Stairs #12

Open
Woodyiiiiiii opened this issue Apr 17, 2020 · 0 comments
Open

LeetCode 70. Climbing Stairs #12

Woodyiiiiiii opened this issue Apr 17, 2020 · 0 comments

Comments

@Woodyiiiiiii
Copy link
Owner

You are climbing a stair case. It takes n steps to reach to the top.

Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?

**Note:**Given n will be a positive integer.

Example 1:

Input: 2
Output: 2
Explanation: There are two ways to climb to the top.
1. 1 step + 1 step
2. 2 steps

Example 2:

Input: 3
Output: 3
Explanation: There are three ways to climb to the top.
1. 1 step + 1 step + 1 step
2. 1 step + 2 steps
3. 2 steps + 1 step

class Solution {
    public int climbStairs(int n) {
        int[] dp = new int[n + 2];
        dp[1] = dp[2] = 1;
        
        for (int i = 3; i <= n + 1; ++i) {
            dp[i] = dp[i - 1] + dp[i - 2];
        }
        
        return dp[n + 1];
    }
}

如果按照“标准”格式,可以这样写:

class Solution {
    public int climbStairs(int n) {
        int[] dp = new int[n + 2];
        dp[1] = dp[2] = 1;
        
        for (int i = 3; i <= n + 1; ++i) {
            for (int way = 1; way <= 2; ++way) {
                dp[i] += dp[i - way];
            }
        }
        
        return dp[n + 1];
    }
}

参考资料:
LeetCode原题

Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment
Labels
None yet
Projects
None yet
Development

No branches or pull requests

1 participant