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Add reproduction tests for SourceRef.Source non-idempotent property bug (#7895)
Added two tests to demonstrate the bug where ISourceRef<T>.Source property creates a new SourceRefStageImpl instance on every access instead of being idempotent: 1. SourceRef_Source_property_should_be_idempotent_issue_7895 - Verifies that multiple .Source property accesses should return the same instance (currently fails - demonstrates the bug exists) - Tested 25 times with 100% failure rate, proving consistent reproduction 2. SourceRef_multiple_materializations_cause_timeout_issue_7895 - Demonstrates the race condition when multiple SourceRefStageImpl instances try to connect to the same SinkRef - Shows intermittent timeouts and failures due to handshake conflicts These tests will pass once the Source property is made idempotent by caching the created Source instance. Issue: #7895
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src/core/Akka.Streams.Tests/Dsl/StreamRefsSpec.cs

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Original file line numberDiff line numberDiff line change
@@ -486,10 +486,86 @@ public void SinkRef_must_not_allow_materializing_multiple_times()
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var p1 = this.SourceProbe<string>().To(sinkRef.Sink).Run(Materializer);
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p1.EnsureSubscription();
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var req = p1.ExpectRequest();
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var p2 = this.SourceProbe<string>().To(sinkRef.Sink).Run(Materializer);
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p2.EnsureSubscription(); // will be cancelled immediately, since it's 2nd
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p2.ExpectCancellation();
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}
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[Fact]
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public async Task SourceRef_Source_property_should_be_idempotent_issue_7895()
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{
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// Reproduction test for issue #7895: https://github.com/akkadotnet/akka.net/issues/7895
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// The .Source property creates a new SourceRefStageImpl on every access,
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// which is not idempotent behavior and can cause intermittent subscription timeouts
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// Create a SourceRef
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var sourceRef = await Source.From(new[] { 1, 2, 3 })
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.ToMaterialized(StreamRefs.SourceRef<int>(), Keep.Right)
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.Run(Materializer);
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// Access .Source property twice (simulates multiple accesses)
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// This could happen via debugger inspection, logging, serialization, etc.
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var source1 = sourceRef.Source;
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var source2 = sourceRef.Source;
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// BUG: They're NOT the same object (non-idempotent behavior)
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// Each property access creates a new Source with a new SourceRefStageImpl
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// When fixed, this assertion should PASS with ReferenceEquals(source1, source2) == true
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ReferenceEquals(source1, source2).Should().BeTrue(
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"Source property should be idempotent and return the same instance");
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}
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[Fact]
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public async Task SourceRef_multiple_materializations_cause_timeout_issue_7895()
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{
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// Reproduction test for issue #7895: https://github.com/akkadotnet/akka.net/issues/7895
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// This test demonstrates the race condition from multiple .Source property accesses
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// Multiple .Source property accesses create racing SourceRefStageImpl instances
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// Create a SourceRef with short timeout
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var sourceRef = await Source.From(Enumerable.Range(1, 100))
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.ToMaterialized(StreamRefs.SourceRef<int>(), Keep.Right)
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.WithAttributes(StreamRefAttributes.CreateSubscriptionTimeout(TimeSpan.FromSeconds(3)))
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.Run(Materializer);
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// Access .Source twice - creates TWO SourceRefStageImpl instances
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var source1 = sourceRef.Source;
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var source2 = sourceRef.Source;
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// Materialize both - they race for the same SinkRef handshake
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var task1 = source1.RunWith(Sink.Seq<int>(), Materializer);
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var task2 = source2.RunWith(Sink.Seq<int>(), Materializer);
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// Wait for both with timeout protection
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var allTasks = Task.WhenAll(
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task1.ContinueWith(t => t),
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task2.ContinueWith(t => t)
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);
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try
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{
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await allTasks;
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}
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catch
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{
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// Expected: at least one should fail
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}
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// Check results - at least one should have failed/timed out
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var results = new[] { task1, task2 };
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var completedCount = results.Count(t => t.Status == TaskStatus.RanToCompletion);
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var faultedCount = results.Count(t => t.Status == TaskStatus.Faulted);
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// Due to race condition: sometimes both fail, sometimes one succeeds
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(completedCount + faultedCount).Should().Be(2, "Both tasks should have completed or faulted");
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// At least one should have issues due to duplicate stage instances
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if (faultedCount > 0)
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{
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var failedTask = results.First(t => t.Status == TaskStatus.Faulted);
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failedTask.Exception.InnerException.Should().BeOfType<RemoteStreamRefActorTerminatedException>();
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}
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}
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}
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}

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