Skip to content

Files

Latest commit

author
Shuo
Jul 10, 2021
62f1dec · Jul 10, 2021

History

History

find-the-longest-substring-containing-vowels-in-even-counts

Folders and files

NameName
Last commit message
Last commit date

parent directory

..
Jul 10, 2021

README.md

< Previous                  Next >

Given the string s, return the size of the longest substring containing each vowel an even number of times. That is, 'a', 'e', 'i', 'o', and 'u' must appear an even number of times.

 

Example 1:

Input: s = "eleetminicoworoep"
Output: 13
Explanation: The longest substring is "leetminicowor" which contains two each of the vowels: e, i and o and zero of the vowels: a and u.

Example 2:

Input: s = "leetcodeisgreat"
Output: 5
Explanation: The longest substring is "leetc" which contains two e's.

Example 3:

Input: s = "bcbcbc"
Output: 6
Explanation: In this case, the given string "bcbcbc" is the longest because all vowels: a, e, i, o and u appear zero times.

 

Constraints:

  • 1 <= s.length <= 5 x 10^5
  • s contains only lowercase English letters.

Related Topics

[Bit Manipulation] [Hash Table] [String] [Prefix Sum]

Hints

Hint 1 Represent the counts (odd or even) of vowels with a bitmask.
Hint 2 Precompute the prefix xor for the bitmask of vowels and then get the longest valid substring.