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dict.c
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dict.c
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/*
* Dictionary Abstract Data Type
* Copyright (C) 1997 Kaz Kylheku <kaz@ashi.footprints.net>
*
* Free Software License:
*
* All rights are reserved by the author, with the following exceptions:
* Permission is granted to freely reproduce and distribute this software,
* possibly in exchange for a fee, provided that this copyright notice appears
* intact. Permission is also granted to adapt this software to produce
* derivative works, as long as the modified versions carry this copyright
* notice and additional notices stating that the work has been modified.
* This source code may be translated into executable form and incorporated
* into proprietary software; there is no requirement for such software to
* contain a copyright notice related to this source.
*
* $Id: dict.c,v 1.15 2005/10/06 05:16:35 kuma Exp $
* $Name: $
*/
/*
* Modified for Ruby/RBTree by OZAWA Takuma.
*/
#include <stdlib.h>
#include <stddef.h>
#include <assert.h>
#include "dict.h"
#include <ruby.h>
#ifdef KAZLIB_RCSID
static const char rcsid[] = "$Id: dict.c,v 1.15 2005/10/06 05:16:35 kuma Exp $";
#endif
/*
* These macros provide short convenient names for structure members,
* which are embellished with dict_ prefixes so that they are
* properly confined to the documented namespace. It's legal for a
* program which uses dict to define, for instance, a macro called ``parent''.
* Such a macro would interfere with the dnode_t struct definition.
* In general, highly portable and reusable C modules which expose their
* structures need to confine structure member names to well-defined spaces.
* The resulting identifiers aren't necessarily convenient to use, nor
* readable, in the implementation, however!
*/
#define left dict_left
#define right dict_right
#define parent dict_parent
#define color dict_color
#define key dict_key
#define data dict_data
#define nilnode dict_nilnode
#define nodecount dict_nodecount
#define compare dict_compare
#define allocnode dict_allocnode
#define freenode dict_freenode
#define context dict_context
#define dupes dict_dupes
#define dictptr dict_dictptr
#define dict_root(D) ((D)->nilnode.left)
#define dict_nil(D) (&(D)->nilnode)
#define DICT_DEPTH_MAX 64
#define COMPARE(dict, key1, key2) dict->compare(key1, key2, dict->context)
static dnode_t *dnode_alloc(void *context);
static void dnode_free(dnode_t *node, void *context);
/*
* Perform a ``left rotation'' adjustment on the tree. The given node P and
* its right child C are rearranged so that the P instead becomes the left
* child of C. The left subtree of C is inherited as the new right subtree
* for P. The ordering of the keys within the tree is thus preserved.
*/
static void rotate_left(dnode_t *upper)
{
dnode_t *lower, *lowleft, *upparent;
lower = upper->right;
upper->right = lowleft = lower->left;
lowleft->parent = upper;
lower->parent = upparent = upper->parent;
/* don't need to check for root node here because root->parent is
the sentinel nil node, and root->parent->left points back to root */
if (upper == upparent->left) {
upparent->left = lower;
} else {
assert (upper == upparent->right);
upparent->right = lower;
}
lower->left = upper;
upper->parent = lower;
}
/*
* This operation is the ``mirror'' image of rotate_left. It is
* the same procedure, but with left and right interchanged.
*/
static void rotate_right(dnode_t *upper)
{
dnode_t *lower, *lowright, *upparent;
lower = upper->left;
upper->left = lowright = lower->right;
lowright->parent = upper;
lower->parent = upparent = upper->parent;
if (upper == upparent->right) {
upparent->right = lower;
} else {
assert (upper == upparent->left);
upparent->left = lower;
}
lower->right = upper;
upper->parent = lower;
}
/*
* Do a postorder traversal of the tree rooted at the specified
* node and free everything under it. Used by dict_free().
*/
static void free_nodes(dict_t *dict, dnode_t *node, dnode_t *nil)
{
if (node == nil)
return;
free_nodes(dict, node->left, nil);
free_nodes(dict, node->right, nil);
dict->freenode(node, dict->context);
}
/*
* This procedure performs a verification that the given subtree is a binary
* search tree. It performs an inorder traversal of the tree using the
* dict_next() successor function, verifying that the key of each node is
* strictly lower than that of its successor, if duplicates are not allowed,
* or lower or equal if duplicates are allowed. This function is used for
* debugging purposes.
*/
static int verify_bintree(dict_t *dict)
{
dnode_t *first, *next;
first = dict_first(dict);
if (dict->dupes) {
while (first && (next = dict_next(dict, first))) {
if (COMPARE(dict, first->key, next->key) > 0)
return 0;
first = next;
}
} else {
while (first && (next = dict_next(dict, first))) {
if (COMPARE(dict, first->key, next->key) >= 0)
return 0;
first = next;
}
}
return 1;
}
/*
* This function recursively verifies that the given binary subtree satisfies
* three of the red black properties. It checks that every red node has only
* black children. It makes sure that each node is either red or black. And it
* checks that every path has the same count of black nodes from root to leaf.
* It returns the blackheight of the given subtree; this allows blackheights to
* be computed recursively and compared for left and right siblings for
* mismatches. It does not check for every nil node being black, because there
* is only one sentinel nil node. The return value of this function is the
* black height of the subtree rooted at the node ``root'', or zero if the
* subtree is not red-black.
*/
static unsigned int verify_redblack(dnode_t *nil, dnode_t *root)
{
unsigned height_left, height_right;
if (root != nil) {
height_left = verify_redblack(nil, root->left);
height_right = verify_redblack(nil, root->right);
if (height_left == 0 || height_right == 0)
return 0;
if (height_left != height_right)
return 0;
if (root->color == dnode_red) {
if (root->left->color != dnode_black)
return 0;
if (root->right->color != dnode_black)
return 0;
return height_left;
}
if (root->color != dnode_black)
return 0;
return height_left + 1;
}
return 1;
}
/*
* Compute the actual count of nodes by traversing the tree and
* return it. This could be compared against the stored count to
* detect a mismatch.
*/
static dictcount_t verify_node_count(dnode_t *nil, dnode_t *root)
{
if (root == nil)
return 0;
else
return 1 + verify_node_count(nil, root->left)
+ verify_node_count(nil, root->right);
}
/*
* Verify that the tree contains the given node. This is done by
* traversing all of the nodes and comparing their pointers to the
* given pointer. Returns 1 if the node is found, otherwise
* returns zero. It is intended for debugging purposes.
*/
static int verify_dict_has_node(dnode_t *nil, dnode_t *root, dnode_t *node)
{
if (root != nil) {
return root == node
|| verify_dict_has_node(nil, root->left, node)
|| verify_dict_has_node(nil, root->right, node);
}
return 0;
}
/*
* Dynamically allocate and initialize a dictionary object.
*/
dict_t *dict_create(dict_comp_t comp)
{
dict_t* new = ALLOC(dict_t);
if (new) {
new->compare = comp;
new->allocnode = dnode_alloc;
new->freenode = dnode_free;
new->context = NULL;
new->nodecount = 0;
new->nilnode.left = &new->nilnode;
new->nilnode.right = &new->nilnode;
new->nilnode.parent = &new->nilnode;
new->nilnode.color = dnode_black;
new->dupes = 0;
}
return new;
}
/*
* Select a different set of node allocator routines.
*/
void dict_set_allocator(dict_t *dict, dnode_alloc_t al,
dnode_free_t fr, void *context)
{
assert (dict_count(dict) == 0);
assert ((al == NULL && fr == NULL) || (al != NULL && fr != NULL));
dict->allocnode = al ? al : dnode_alloc;
dict->freenode = fr ? fr : dnode_free;
dict->context = context;
}
/*
* Free a dynamically allocated dictionary object. Removing the nodes
* from the tree before deleting it is required.
*/
void dict_destroy(dict_t *dict)
{
assert (dict_isempty(dict));
xfree(dict);
}
/*
* Free all the nodes in the dictionary by using the dictionary's
* installed free routine. The dictionary is emptied.
*/
void dict_free_nodes(dict_t *dict)
{
dnode_t *nil = dict_nil(dict), *root = dict_root(dict);
free_nodes(dict, root, nil);
dict->nodecount = 0;
dict->nilnode.left = &dict->nilnode;
dict->nilnode.right = &dict->nilnode;
dict->nilnode.parent = &dict->nilnode;
}
/*
* Obsolescent function, equivalent to dict_free_nodes
*/
void dict_free(dict_t *dict)
{
#ifdef KAZLIB_OBSOLESCENT_DEBUG
assert ("call to obsolescent function dict_free()" && 0);
#endif
dict_free_nodes(dict);
}
/*
* Initialize a user-supplied dictionary object.
*/
dict_t *dict_init(dict_t *dict, dict_comp_t comp)
{
dict->compare = comp;
dict->allocnode = dnode_alloc;
dict->freenode = dnode_free;
dict->context = NULL;
dict->nodecount = 0;
dict->nilnode.left = &dict->nilnode;
dict->nilnode.right = &dict->nilnode;
dict->nilnode.parent = &dict->nilnode;
dict->nilnode.color = dnode_black;
dict->dupes = 0;
return dict;
}
/*
* Initialize a dictionary in the likeness of another dictionary
*/
void dict_init_like(dict_t *dict, const dict_t *template)
{
dict->compare = template->compare;
dict->allocnode = template->allocnode;
dict->freenode = template->freenode;
dict->context = template->context;
dict->nodecount = 0;
dict->nilnode.left = &dict->nilnode;
dict->nilnode.right = &dict->nilnode;
dict->nilnode.parent = &dict->nilnode;
dict->nilnode.color = dnode_black;
dict->dupes = template->dupes;
assert (dict_similar(dict, template));
}
/*
* Remove all nodes from the dictionary (without freeing them in any way).
*/
static void dict_clear(dict_t *dict)
{
dict->nodecount = 0;
dict->nilnode.left = &dict->nilnode;
dict->nilnode.right = &dict->nilnode;
dict->nilnode.parent = &dict->nilnode;
assert (dict->nilnode.color == dnode_black);
}
/*
* Verify the integrity of the dictionary structure. This is provided for
* debugging purposes, and should be placed in assert statements. Just because
* this function succeeds doesn't mean that the tree is not corrupt. Certain
* corruptions in the tree may simply cause undefined behavior.
*/
int dict_verify(dict_t *dict)
{
dnode_t *nil = dict_nil(dict), *root = dict_root(dict);
/* check that the sentinel node and root node are black */
if (root->color != dnode_black)
return 0;
if (nil->color != dnode_black)
return 0;
if (nil->right != nil)
return 0;
/* nil->left is the root node; check that its parent pointer is nil */
if (nil->left->parent != nil)
return 0;
/* perform a weak test that the tree is a binary search tree */
if (!verify_bintree(dict))
return 0;
/* verify that the tree is a red-black tree */
if (!verify_redblack(nil, root))
return 0;
if (verify_node_count(nil, root) != dict_count(dict))
return 0;
return 1;
}
/*
* Determine whether two dictionaries are similar: have the same comparison and
* allocator functions, and same status as to whether duplicates are allowed.
*/
int dict_similar(const dict_t *left, const dict_t *right)
{
if (left->compare != right->compare)
return 0;
if (left->allocnode != right->allocnode)
return 0;
if (left->freenode != right->freenode)
return 0;
if (left->context != right->context)
return 0;
/* if (left->dupes != right->dupes) */
/* return 0; */
return 1;
}
/*
* Locate a node in the dictionary having the given key.
* If the node is not found, a null a pointer is returned (rather than
* a pointer that dictionary's nil sentinel node), otherwise a pointer to the
* located node is returned.
*/
dnode_t *dict_lookup(dict_t *dict, const void *key)
{
dnode_t *root = dict_root(dict);
dnode_t *nil = dict_nil(dict);
dnode_t *saved;
int result;
/* simple binary search adapted for trees that contain duplicate keys */
while (root != nil) {
result = COMPARE(dict, key, root->key);
if (result < 0)
root = root->left;
else if (result > 0)
root = root->right;
else {
if (!dict->dupes) { /* no duplicates, return match */
return root;
} else { /* could be dupes, find leftmost one */
do {
saved = root;
root = root->left;
while (root != nil && COMPARE(dict, key, root->key))
root = root->right;
} while (root != nil);
return saved;
}
}
}
return NULL;
}
/*
* Look for the node corresponding to the lowest key that is equal to or
* greater than the given key. If there is no such node, return null.
*/
dnode_t *dict_lower_bound(dict_t *dict, const void *key)
{
dnode_t *root = dict_root(dict);
dnode_t *nil = dict_nil(dict);
dnode_t *tentative = 0;
while (root != nil) {
int result = COMPARE(dict, key, root->key);
if (result > 0) {
root = root->right;
} else if (result < 0) {
tentative = root;
root = root->left;
} else {
if (!dict->dupes) {
return root;
} else {
tentative = root;
root = root->left;
}
}
}
return tentative;
}
/*
* Look for the node corresponding to the greatest key that is equal to or
* lower than the given key. If there is no such node, return null.
*/
dnode_t *dict_upper_bound(dict_t *dict, const void *key)
{
dnode_t *root = dict_root(dict);
dnode_t *nil = dict_nil(dict);
dnode_t *tentative = 0;
while (root != nil) {
int result = COMPARE(dict, key, root->key);
if (result < 0) {
root = root->left;
} else if (result > 0) {
tentative = root;
root = root->right;
} else {
if (!dict->dupes) {
return root;
} else {
tentative = root;
root = root->right;
}
}
}
return tentative;
}
/*
* Insert a node into the dictionary. The node should have been
* initialized with a data field. All other fields are ignored.
* The behavior is undefined if the user attempts to insert into
* a dictionary that is already full (for which the dict_isfull()
* function returns true).
*/
int dict_insert(dict_t *dict, dnode_t *node, const void *key)
{
dnode_t *where = dict_root(dict), *nil = dict_nil(dict);
dnode_t *parent = nil, *uncle, *grandpa;
int result = -1;
node->key = key;
assert (!dict_isfull(dict));
assert (!dict_contains(dict, node));
assert (!dnode_is_in_a_dict(node));
/* basic binary tree insert */
while (where != nil) {
parent = where;
result = COMPARE(dict, key, where->key);
/* trap attempts at duplicate key insertion unless it's explicitly allowed */
if (!dict->dupes && result == 0) {
where->data = node->data;
return 0;
} else if (result < 0) {
where = where->left;
} else {
where = where->right;
}
}
assert (where == nil);
if (result < 0)
parent->left = node;
else
parent->right = node;
node->parent = parent;
node->left = nil;
node->right = nil;
dict->nodecount++;
/* red black adjustments */
node->color = dnode_red;
while (parent->color == dnode_red) {
grandpa = parent->parent;
if (parent == grandpa->left) {
uncle = grandpa->right;
if (uncle->color == dnode_red) { /* red parent, red uncle */
parent->color = dnode_black;
uncle->color = dnode_black;
grandpa->color = dnode_red;
node = grandpa;
parent = grandpa->parent;
} else { /* red parent, black uncle */
if (node == parent->right) {
rotate_left(parent);
parent = node;
assert (grandpa == parent->parent);
/* rotation between parent and child preserves grandpa */
}
parent->color = dnode_black;
grandpa->color = dnode_red;
rotate_right(grandpa);
break;
}
} else { /* symmetric cases: parent == parent->parent->right */
uncle = grandpa->left;
if (uncle->color == dnode_red) {
parent->color = dnode_black;
uncle->color = dnode_black;
grandpa->color = dnode_red;
node = grandpa;
parent = grandpa->parent;
} else {
if (node == parent->left) {
rotate_right(parent);
parent = node;
assert (grandpa == parent->parent);
}
parent->color = dnode_black;
grandpa->color = dnode_red;
rotate_left(grandpa);
break;
}
}
}
dict_root(dict)->color = dnode_black;
assert (dict_verify(dict));
return 1;
}
/*
* Delete the given node from the dictionary. If the given node does not belong
* to the given dictionary, undefined behavior results. A pointer to the
* deleted node is returned.
*/
dnode_t *dict_delete(dict_t *dict, dnode_t *delete)
{
dnode_t *nil = dict_nil(dict), *child, *delparent = delete->parent;
/* basic deletion */
assert (!dict_isempty(dict));
assert (dict_contains(dict, delete));
/*
* If the node being deleted has two children, then we replace it with its
* successor (i.e. the leftmost node in the right subtree.) By doing this,
* we avoid the traditional algorithm under which the successor's key and
* value *only* move to the deleted node and the successor is spliced out
* from the tree. We cannot use this approach because the user may hold
* pointers to the successor, or nodes may be inextricably tied to some
* other structures by way of embedding, etc. So we must splice out the
* node we are given, not some other node, and must not move contents from
* one node to another behind the user's back.
*/
if (delete->left != nil && delete->right != nil) {
dnode_t *next = dict_next(dict, delete);
dnode_t *nextparent = next->parent;
dnode_color_t nextcolor = next->color;
assert (next != nil);
assert (next->parent != nil);
assert (next->left == nil);
/*
* First, splice out the successor from the tree completely, by
* moving up its right child into its place.
*/
child = next->right;
child->parent = nextparent;
if (nextparent->left == next) {
nextparent->left = child;
} else {
assert (nextparent->right == next);
nextparent->right = child;
}
/*
* Now that the successor has been extricated from the tree, install it
* in place of the node that we want deleted.
*/
next->parent = delparent;
next->left = delete->left;
next->right = delete->right;
next->left->parent = next;
next->right->parent = next;
next->color = delete->color;
delete->color = nextcolor;
if (delparent->left == delete) {
delparent->left = next;
} else {
assert (delparent->right == delete);
delparent->right = next;
}
} else {
assert (delete != nil);
assert (delete->left == nil || delete->right == nil);
child = (delete->left != nil) ? delete->left : delete->right;
child->parent = delparent = delete->parent;
if (delete == delparent->left) {
delparent->left = child;
} else {
assert (delete == delparent->right);
delparent->right = child;
}
}
delete->parent = NULL;
delete->right = NULL;
delete->left = NULL;
dict->nodecount--;
assert (verify_bintree(dict));
/* red-black adjustments */
if (delete->color == dnode_black) {
dnode_t *parent, *sister;
dict_root(dict)->color = dnode_red;
while (child->color == dnode_black) {
parent = child->parent;
if (child == parent->left) {
sister = parent->right;
assert (sister != nil);
if (sister->color == dnode_red) {
sister->color = dnode_black;
parent->color = dnode_red;
rotate_left(parent);
sister = parent->right;
assert (sister != nil);
}
if (sister->left->color == dnode_black
&& sister->right->color == dnode_black) {
sister->color = dnode_red;
child = parent;
} else {
if (sister->right->color == dnode_black) {
assert (sister->left->color == dnode_red);
sister->left->color = dnode_black;
sister->color = dnode_red;
rotate_right(sister);
sister = parent->right;
assert (sister != nil);
}
sister->color = parent->color;
sister->right->color = dnode_black;
parent->color = dnode_black;
rotate_left(parent);
break;
}
} else { /* symmetric case: child == child->parent->right */
assert (child == parent->right);
sister = parent->left;
assert (sister != nil);
if (sister->color == dnode_red) {
sister->color = dnode_black;
parent->color = dnode_red;
rotate_right(parent);
sister = parent->left;
assert (sister != nil);
}
if (sister->right->color == dnode_black
&& sister->left->color == dnode_black) {
sister->color = dnode_red;
child = parent;
} else {
if (sister->left->color == dnode_black) {
assert (sister->right->color == dnode_red);
sister->right->color = dnode_black;
sister->color = dnode_red;
rotate_left(sister);
sister = parent->left;
assert (sister != nil);
}
sister->color = parent->color;
sister->left->color = dnode_black;
parent->color = dnode_black;
rotate_right(parent);
break;
}
}
}
child->color = dnode_black;
dict_root(dict)->color = dnode_black;
}
assert (dict_verify(dict));
return delete;
}
/*
* Allocate a node using the dictionary's allocator routine, give it
* the data item.
*/
int dict_alloc_insert(dict_t *dict, const void *key, void *data)
{
dnode_t *node = dict->allocnode(dict->context);
if (node) {
dnode_init(node, data);
if (!dict_insert(dict, node, key))
dict->freenode(node, dict->context);
return 1;
}
return 0;
}
void dict_delete_free(dict_t *dict, dnode_t *node)
{
dict_delete(dict, node);
dict->freenode(node, dict->context);
}
/*
* Return the node with the lowest (leftmost) key. If the dictionary is empty
* (that is, dict_isempty(dict) returns 1) a null pointer is returned.
*/
dnode_t *dict_first(dict_t *dict)
{
dnode_t *nil = dict_nil(dict), *root = dict_root(dict), *left;
if (root != nil)
while ((left = root->left) != nil)
root = left;
return (root == nil) ? NULL : root;
}
/*
* Return the node with the highest (rightmost) key. If the dictionary is empty
* (that is, dict_isempty(dict) returns 1) a null pointer is returned.
*/
dnode_t *dict_last(dict_t *dict)
{
dnode_t *nil = dict_nil(dict), *root = dict_root(dict), *right;
if (root != nil)
while ((right = root->right) != nil)
root = right;
return (root == nil) ? NULL : root;
}
/*
* Return the given node's successor node---the node which has the
* next key in the the left to right ordering. If the node has
* no successor, a null pointer is returned rather than a pointer to
* the nil node.
*/
dnode_t *dict_next(dict_t *dict, dnode_t *curr)
{
dnode_t *nil = dict_nil(dict), *parent, *left;
if (curr->right != nil) {
curr = curr->right;
while ((left = curr->left) != nil)
curr = left;
return curr;
}
parent = curr->parent;
while (parent != nil && curr == parent->right) {
curr = parent;
parent = curr->parent;
}
return (parent == nil) ? NULL : parent;
}
/*
* Return the given node's predecessor, in the key order.
* The nil sentinel node is returned if there is no predecessor.
*/
dnode_t *dict_prev(dict_t *dict, dnode_t *curr)
{
dnode_t *nil = dict_nil(dict), *parent, *right;
if (curr->left != nil) {
curr = curr->left;
while ((right = curr->right) != nil)
curr = right;
return curr;
}
parent = curr->parent;
while (parent != nil && curr == parent->left) {
curr = parent;
parent = curr->parent;
}
return (parent == nil) ? NULL : parent;
}
void dict_allow_dupes(dict_t *dict)
{
dict->dupes = 1;
}
dictcount_t dict_count(dict_t *dict)
{
return dict->nodecount;
}
int dict_isempty(dict_t *dict)
{
return dict->nodecount == 0;
}
int dict_isfull(dict_t *dict)
{
return dict->nodecount == DICTCOUNT_T_MAX;
}
int dict_contains(dict_t *dict, dnode_t *node)
{
return verify_dict_has_node(dict_nil(dict), dict_root(dict), node);
}
static dnode_t *dnode_alloc(void *context)
{
return malloc(sizeof *dnode_alloc(NULL));
}
static void dnode_free(dnode_t *node, void *context)
{
free(node);
}
dnode_t *dnode_create(void *data)
{
dnode_t *new = malloc(sizeof *new);
if (new) {
new->data = data;
new->parent = NULL;
new->left = NULL;
new->right = NULL;
}
return new;
}
dnode_t *dnode_init(dnode_t *dnode, void *data)
{
dnode->data = data;
dnode->parent = NULL;
dnode->left = NULL;
dnode->right = NULL;
return dnode;
}
void dnode_destroy(dnode_t *dnode)
{
assert (!dnode_is_in_a_dict(dnode));
free(dnode);
}
void *dnode_get(dnode_t *dnode)
{
return dnode->data;
}
const void *dnode_getkey(dnode_t *dnode)
{
return dnode->key;
}
void dnode_put(dnode_t *dnode, void *data)
{
dnode->data = data;