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p006.py
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p006.py
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# The sum of the squares of the first ten natural numbers is,
# 12 + 22 + ... + 102 = 385
# The square of the sum of the first ten natural numbers is,
# (1 + 2 + ... + 10)2 = 552 = 3025
# Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.
# Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.
def compute():
ran = range(1,101)
sum1 = 0
sum2 = 0
for x in ran:
sum1 += (x * x)
sum2 += x
return((sum2 * sum2) - sum1)
if __name__ == "__main__":
print(compute())