/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
void flatten(TreeNode* root) {
if (!root) return ;
//将根节点的左子树变成链表
flatten(root -> left);
//将根节点的右子树变成链表
flatten(root -> right);
TreeNode* temp = root->right;
//把树的右边换成左边的链表
root->right = root->left;
//记得要将左边置空
root->left = NULL;
//找到树的最右边的节点
while (root->right != NULL) root = root->right;
//把右边的链表接到刚才树的最右边的节点
root->right =temp;
return ;
}
};