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04.py
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from common.util import *
from typing import List
# --- Day 4: Passport Processing ---
# You arrive at the airport only to realize that you grabbed your North Pole Credentials instead of your passport.
# While these documents are extremely similar,
# North Pole Credentials aren't issued by a country and therefore aren't actually valid documentation for travel in most of the world.
# It seems like you're not the only one having problems, though;
# a very long line has formed for the automatic passport scanners, and the delay could upset your travel itinerary.
# Due to some questionable network security, you realize you might be able to solve both of these problems at the same time.
# The automatic passport scanners are slow because they're having trouble detecting which passports have all required fields.
# The expected fields are as follows:
# byr (Birth Year)
# iyr (Issue Year)
# eyr (Expiration Year)
# hgt (Height)
# hcl (Hair Color)
# ecl (Eye Color)
# pid (Passport ID)
# cid (Country ID)
# Passport data is validated in batch files (your puzzle input).
# Each passport is represented as a sequence of key:value pairs separated by spaces or newlines.Passports are separated by blank lines.
# Here is an example batch file containing four passports:
# ecl:gry pid:860033327 eyr:2020 hcl:#fffffd
# byr:1937 iyr:2017 cid:147 hgt:183cm
# iyr:2013 ecl:amb cid:350 eyr:2023 pid:028048884
# hcl:#cfa07d byr:1929
# hcl:#ae17e1 iyr:2013
# eyr:2024
# ecl:brn pid:760753108 byr:1931
# hgt:179cm
# hcl:#cfa07d eyr:2025 pid:166559648
# iyr:2011 ecl:brn hgt:59in
# The first passport is valid - all eight fields are present. The second passport is invalid - it is missing hgt (the Height field).
# The third passport is interesting; the only missing field is cid,so it looks like data from North Pole Credentials, not a passport at all!
# Surely, nobody would mind if you made the system temporarily ignore missing cid fields. Treat this "passport" as valid.
# The fourth passport is missing two fields, cid and byr. Missing cid is fine, but missing any other field is not, so this passport is invalid.
# According to the above rules, your improved system would report 2 valid passports.
# Count the number of valid passports - those that have all required fields. Treat cid as optional. In your batch file, how many passports are valid?
def part1(data):
valids = ["byr", "iyr", "eyr", "hgt", "hcl", "ecl", "pid"]
count, passports, line = 0, [], set()
# Parse passports
for i, item in enumerate(data):
if item != "":
for attrs in item.split(" "):
line.add(attrs[:3])
if i == len(data) - 1 or item == "":
passports.append(line)
line = set()
# Check valid passport
for passport in passports:
if all(v in passport for v in valids):
count += 1
return count
print(solution("day04", part1, line_parser))
# --- Part Two ---
# The line is moving more quickly now, but you overhear airport security talking about how passports with invalid data are getting through.
# Better add some data validation, quick!
# You can continue to ignore the cid field, but each other field has strict rules about what values are valid for automatic validation:
# byr (Birth Year) - four digits; at least 1920 and at most 2002.
# iyr (Issue Year) - four digits; at least 2010 and at most 2020.
# eyr (Expiration Year) - four digits; at least 2020 and at most 2030.
# hgt (Height) - a number followed by either cm or in:
# If cm, the number must be at least 150 and at most 193.
# If in, the number must be at least 59 and at most 76.
# hcl (Hair Color) - a # followed by exactly six characters 0-9 or a-f.
# ecl (Eye Color) - exactly one of: amb blu brn gry grn hzl oth.
# pid (Passport ID) - a nine-digit number, including leading zeroes.
# cid (Country ID) - ignored, missing or not.
# Your job is to count the passports where all required fields are both present and valid according to the above rules. Here are some example values:
# byr valid: 2002
# byr invalid: 2003
# hgt valid: 60in
# hgt valid: 190cm
# hgt invalid: 190in
# hgt invalid: 190
# hcl valid: #123abc
# hcl invalid: #123abz
# hcl invalid: 123abc
# ecl valid: brn
# ecl invalid: wat
# pid valid: 000000001
# pid invalid: 0123456789
# Here are some invalid passports:
# eyr:1972 cid:100
# hcl:#18171d ecl:amb hgt:170 pid:186cm iyr:2018 byr:1926
# iyr:2019
# hcl:#602927 eyr:1967 hgt:170cm
# ecl:grn pid:012533040 byr:1946
# hcl:dab227 iyr:2012
# ecl:brn hgt:182cm pid:021572410 eyr:2020 byr:1992 cid:277
# hgt:59cm ecl:zzz
# eyr:2038 hcl:74454a iyr:2023
# pid:3556412378 byr:2007
# Here are some valid passports:
# pid:087499704 hgt:74in ecl:grn iyr:2012 eyr:2030 byr:1980
# hcl:#623a2f
# eyr:2029 ecl:blu cid:129 byr:1989
# iyr:2014 pid:896056539 hcl:#a97842 hgt:165cm
# hcl:#888785
# hgt:164cm byr:2001 iyr:2015 cid:88
# pid:545766238 ecl:hzl
# eyr:2022
# iyr:2010 hgt:158cm hcl:#b6652a ecl:blu byr:1944 eyr:2021 pid:093154719
# Count the number of valid passports - those that have all required fields and valid values.
# Continue to treat cid as optional. In your batch file, how many passports are valid?
def part2(data):
valids = ["byr", "iyr", "eyr", "hgt", "hcl", "ecl", "pid"]
count, passports, passport = 0, [], dict()
# Parse passports
for i, item in enumerate(data):
if item != "":
for field in item.split(" "):
passport[field[:3]] = field[4:]
if i == len(data) - 1 or item == "":
passports.append(passport)
passport = dict()
# Check valid passport
for passport in passports:
# byr (Birth Year) - four digits; at least 1920 and at most 2002.
# iyr (Issue Year) - four digits; at least 2010 and at most 2020.
# eyr (Expiration Year) - four digits; at least 2020 and at most 2030.
# hgt (Height) - a number followed by either cm or in:
# If cm, the number must be at least 150 and at most 193.
# If in, the number must be at least 59 and at most 76.
# hcl (Hair Color) - a # followed by exactly six characters 0-9 or a-f.
# ecl (Eye Color) - exactly one of: amb blu brn gry grn hzl oth.
# pid (Passport ID) - a nine-digit number, including leading zeroes.
if all(v in passport for v in valids):
byr = 1920 <= int(passport["byr"]) <= 2002
iyr = 2010 <= int(passport["iyr"]) <= 2020
eyr = 2020 <= int(passport["eyr"]) <= 2030
hgt_unit, hgt_value = passport["hgt"][-2:], passport["hgt"][:-2]
if hgt_unit == "cm":
hgt = 150 <= int(hgt_value) <= 193
elif hgt_unit == "in":
hgt = 59 <= int(hgt_value) <= 76
else:
hgt = False
hcl = passport["hcl"][0] == "#" and passport["hcl"][1:].isalnum()
ecl = any(
v in passport["ecl"]
for v in ["amb", "blu", "brn", "gry", "grn", "hzl", "oth"]
)
pid = len(passport["pid"]) == 9 and passport["pid"].isnumeric()
count += all([byr, iyr, eyr, hgt, hcl, ecl, pid])
return count
print(solution("day04", part2, line_parser))