Given a 1-indexed array of integers numbers that is already sorted in non-decreasing order, find two numbers such that they add up to a specific target number. Let these two numbers be numbers[index1] and numbers[index2] where 1 <= index1 < index2 <= numbers.length.
Return the indices of the two numbers, index1 and index2, added by one as an integer array [index1, index2] of length 2.
The tests are generated such that there is exactly one solution. You may not use the same element twice.
/**
* @param {number[]} numbers
* @param {number} target
* @return {number[]}
*/
var twoSum = function(numbers, target) {
const map = new Map();
for(let i = 0; i < numbers.length; i++) {
if(map.has(target - numbers[i])) {
return [map.get(target - numbers[i]), i + 1];
}
map.set(numbers[i], i + 1);
}
return -1;
};