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<p>为了让同学们适应期末考试,每日一题的题面都将使用英文描述。</p>
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<h3 id="7-the-differance-between-strlen-and-sizeof">「7」 The differance between <code>strlen</code> and <code>sizeof</code>.<a class="headerlink" href="#7-the-differance-between-strlen-and-sizeof" title="Permanent link"></a></h3>
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<h3 id="8-j-lost">「8」 J lost<a class="headerlink" href="#8-j-lost" title="Permanent link"></a></h3>
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<p>Given the following program:</p>
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<div class="highlight"><table class="highlighttable"><tr><td class="linenos"><div class="linenodiv"><pre><span></span><span class="normal"> 1</span>
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<span class="normal">16</span></pre></div></td><td class="code"><div><pre><span></span><code><span class="kt">void</span><span class="w"> </span><span class="nf">xqc</span><span class="p">(</span><span class="kt">char</span><span class="w"> </span><span class="n">c</span><span class="p">[],</span><span class="w"> </span><span class="kt">int</span><span class="w"> </span><span class="n">i</span><span class="p">);</span>
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<span class="kt">int</span><span class="w"> </span><span class="nf">main</span><span class="p">(</span><span class="kt">void</span><span class="p">)</span><span class="w"> </span><span class="p">{</span>
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<span class="w"> </span><span class="kt">char</span><span class="w"> </span><span class="n">c</span><span class="p">[]</span><span class="w"> </span><span class="o">=</span><span class="w"> </span><span class="s">"I am a Man of Fortune"</span><span class="p">;</span>
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<span class="w"> </span><span class="kt">char</span><span class="w"> </span><span class="n">d</span><span class="p">[]</span><span class="w"> </span><span class="o">=</span><span class="w"> </span><span class="s">"and I must seek my Fortune"</span><span class="p">;</span>
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<span class="hll"><span class="w"> </span><span class="n">xqc</span><span class="p">(</span><span class="n">c</span><span class="w"> </span><span class="o">+</span><span class="w"> </span><span class="mi">1</span><span class="p">,</span><span class="w"> </span><span class="o">~</span><span class="mi">1694</span><span class="p">);</span>
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</span><span class="w"> </span><span class="n">xqc</span><span class="p">(</span><span class="n">d</span><span class="w"> </span><span class="o">-</span><span class="w"> </span><span class="o">~</span><span class="mi">3</span><span class="p">,</span><span class="w"> </span><span class="mi">-65</span><span class="p">);</span>
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<span class="w"> </span><span class="n">printf</span><span class="p">(</span><span class="s">"%s, %s</span><span class="se">\n</span><span class="s">"</span><span class="p">,</span><span class="w"> </span><span class="n">c</span><span class="p">,</span><span class="w"> </span><span class="n">d</span><span class="p">);</span>
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<span class="kt">void</span><span class="w"> </span><span class="nf">xqc</span><span class="p">(</span><span class="kt">char</span><span class="w"> </span><span class="n">c</span><span class="p">[],</span><span class="w"> </span><span class="kt">int</span><span class="w"> </span><span class="n">i</span><span class="p">)</span><span class="w"> </span><span class="p">{</span>
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<span class="w"> </span><span class="n">c</span><span class="p">[</span><span class="mi">1</span><span class="p">]</span><span class="w"> </span><span class="o">=</span><span class="w"> </span><span class="p">(</span><span class="n">i</span><span class="w"> </span><span class="o">&amp;</span><span class="w"> </span><span class="mi">1</span><span class="p">)</span><span class="w"> </span><span class="o">+</span><span class="w"> </span><span class="sc">'I'</span><span class="p">;</span>
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</code></pre></div></td></tr></table></div>
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<p>Which of the following is correct?</p>
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<p>A. This program fails to compile, because you cannot assign to an array in line 13.</p>
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<p>B. Because of the call-by-value, function <code>xqc</code> cannot modify the character arrays in function <code>main</code>.</p>
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<p>C. Change <code>1694</code> in line 7 to <code>1994</code>, and the result of the program is the same.</p>
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<p>D. This program outputs <code>I am a Man of Fortune, and J must seek my Fortune</code>.</p>
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<!-- prettier-ignore-start -->
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<details class="note">
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<summary>Answer</summary>
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<p>C.</p>
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<p>A: Inside function <code>xqc</code>, <code>c</code> is a pointer type <code>char *</code> rather than an array type, because when an array type is used in a function parameter list, it actually is the corresponding pointer type. Therefore, the assignment in line 13 is valid, and it means "to move the pointer <code>c</code> one position backward".</p>
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<p>B: The function <code>xqc</code> can modify the character arrays in function <code>main</code>, because it takes the address of the character arrays as parameters. The function <code>xqc</code> can modify the contents of the character arrays through the pointers.</p>
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<p>C: The <code>~</code> operator is the bitwise NOT operator. The <code>~1694</code> is equivalent to <code>-1695</code>. The <code>~3</code> is equivalent to <code>-4</code>. Therefore, the calls to function <code>xqc</code> are equivalent to:</p>
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<div class="highlight"><pre><span></span><code><span class="n">xqc</span><span class="p">(</span><span class="n">c</span><span class="w"> </span><span class="o">+</span><span class="w"> </span><span class="mi">1</span><span class="p">,</span><span class="w"> </span><span class="mi">-1695</span><span class="p">);</span>
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<span class="n">xqc</span><span class="p">(</span><span class="n">d</span><span class="w"> </span><span class="o">-</span><span class="w"> </span><span class="mi">-4</span><span class="p">,</span><span class="w"> </span><span class="mi">-65</span><span class="p">);</span>
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</code></pre></div>
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<p>And <code>i &amp; 1</code> gets the last bit of <code>i</code>. Both <code>-1695</code> and <code>-65</code> are odd numbers, so <code>i &amp; 1</code> is <code>1</code>, and the character <code>1 + 'I'</code>, which is <code>'J'</code>, is assigned. Changing <code>1694</code> to <code>1994</code> does not change the result of the program, because <code>~1994</code> is <code>-1995</code>, and <code>-1995</code> is also an odd number.</p>
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<p>D: This program outputs <code> Jam a Man of Fortune, and J must seek my Fortune</code>.</p>
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<div class="admonition tip">
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<p class="admonition-title">Tip</p>
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<p>You don't need to calculate the exact value of <code>~1694</code>. All you need to know is that the last bit of <code>1694</code> is 0 (since it is an even number), and the bitwise NOT operator will reverse that last bit. Therefore, <code>~1694</code> is an odd number, and <code>i &amp; 1</code> is <code>1</code>. Ditto for <code>~1994</code>.</p>
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</div>
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</details>
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<!-- prettier-ignore-end -->
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<blockquote>
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<p>供题人:李英琦</p>
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</blockquote>
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