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Copy path1170. Compare Strings by Frequency of the Smallest Character.cpp
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1170. Compare Strings by Frequency of the Smallest Character.cpp
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Let's define a function f(s) over a non-empty string s, which calculates the frequency of the smallest character in s. For example, if s = "dcce" then f(s) = 2 because the smallest character is "c" and its frequency is 2.
Now, given string arrays queries and words, return an integer array answer, where each answer[i] is the number of words such that f(queries[i]) < f(W), where W is a word in words.
Example 1:
Input: queries = ["cbd"], words = ["zaaaz"]
Output: [1]
Explanation: On the first query we have f("cbd") = 1, f("zaaaz") = 3 so f("cbd") < f("zaaaz").
Example 2:
Input: queries = ["bbb","cc"], words = ["a","aa","aaa","aaaa"]
Output: [1,2]
Explanation: On the first query only f("bbb") < f("aaaa"). On the second query both f("aaa") and f("aaaa") are both > f("cc").
Constraints:
1 <= queries.length <= 2000
1 <= words.length <= 2000
1 <= queries[i].length, words[i].length <= 10
queries[i][j], words[i][j] are English lowercase letters.
class Solution {
public:
vector<int> numSmallerByFrequency(vector<string>& queries, vector<string>& words) {
vector<int> res;
vector<int> wordFreq;
for(auto word: words){
vector<int> freq(26, 0);
for(int i=0;i<word.length();i++){
freq[word[i]-'a']++;
}
for(int i=0;i<26;i++){
if(freq[i]>0){
wordFreq.push_back(freq[i]);
break;
}
}
}
for(auto query: queries){
vector<int> freq(26, 0);
for(int i=0;i<query.length();i++){
freq[query[i]-'a']++;
}
int tmp=0, mini=0;
for(int i=0;i<26;i++){
if(freq[i]>0){
mini=freq[i];
break;
}
}
int cnt=0;
for(int i=0;i<wordFreq.size();i++){
if(mini<wordFreq[i])
cnt++;
}
res.push_back(cnt);
}
return res;
}
};