Changed

Author: codingbychanche

Readme.md

@@ -8,56 +8,56 @@ Beam and acting loads
 Sample output
 -------------
 	Beam:
-Length=4.0
-Supports sorted by distance from left end of beam:
-Support A (Left)    xn=1.0
-Support B (Right)    xn=3.0
-
-Number of Loads:2
-Loads sorted by distance from left end of beam:
-Name:q1 Magnitute at start:-5.0 Point Load:-5.0 distance from left end:0.0 Lengtht:4.0  Force at end:-5.0 Resulting force:-20.0 is acting 2.0 m from left end of beam.
-Name:F1 Magnitute at start:-2.0 Point Load:-2.0 distance from left end:2.0 Lengtht:0.0  Force at end:-2.0 Resulting force:-2.0 is acting 2.0 m from left end of beam.
-
-RESULT:
-Left support:11.0 N. Right bearing:11.0 N.
-Horizontal force at right support:0.0
-Term:N=0.00N
-Term:B (Right)=5.0N x 4.0m + 2.0N + (-11.00N) = 11.00N
-Term:A (Left)=(5.0 N/m x 4.0m x 1.0m+2.0N x 1.0m)/2.0m = 11.00N
-
-=== Shearing forces => Q ===
-Local maxi-/  minima
-Points of disconuity in Q
-x=0.0 m   Q=-0.01 N
-x=1.0 m   Q=5.995000000000084 N
-x=2.0 m   Q=-1.0099999999998097 N
-x=3.0 m   Q=4.990000000000296 N
-x=3.9999999999996705 m   Q=-0.009999999999619792 N
-Zero points in Q
-x=0.9980000000000008 m
-x=1.9989999999998906 m
-x=2.9989999999997807 m
-x=3.9979999999996707 m
-
-=== Bending moment => M ===
-Local maxi-/  minima
-x=0.0 m   M=0.0 Nm
-x=0.9980000000000008 m   M=-2.5049725149999653 Nm
-x=1.9989999999998906 m   M=0.9970029950001726 Nm
-x=2.9989999999997807 m   M=-2.5269875049995836 Nm
-x=3.9979999999996707 m   M=-0.018966014999237325 Nm
-Points of disconuity in M
-x=0.9990000000000008 m   M=-2.488004504999965 Nm
-x=1.9999999999998905 m   M=0.991985000000173 Nm
-x=2.9999999999997806 m   M=-2.4890234999995826 Nm
-Zero points in M
-x=0.0 m
-x=1.5339999999999419 m
-x=2.4569999999998404 m
-x=3.9999999999996705 m
-
-=== Normal forces => N ===
-x=2.0 m   N[N]=0.0 NBeam Calc
+	Length=4.0
+	Supports sorted by distance from left end of beam:
+	Support A (Left)    xn=1.0
+	Support B (Right)    xn=3.0
+
+	Number of Loads:2
+	Loads sorted by distance from left end of beam:
+	Name:q1 Magnitute at start:-5.0 Point Load:-5.0 distance from left end:0.0 Lengtht:4.0  Force at end:-5.0 Resulting force:-20.0 is acting 2.0 m from left end of beam.
+	Name:F1 Magnitute at start:-2.0 Point Load:-2.0 distance from left end:2.0 Lengtht:0.0  Force at end:-2.0 Resulting force:-2.0 is acting 2.0 m from left end of beam.
+
+	RESULT:
+	Left support:11.0 N. Right bearing:11.0 N.
+	Horizontal force at right support:0.0
+	Term:N=0.00N
+	Term:B (Right)=5.0N x 4.0m + 2.0N + (-11.00N) = 11.00N
+	Term:A (Left)=(5.0 N/m x 4.0m x 1.0m+2.0N x 1.0m)/2.0m = 11.00N
+
+	=== Shearing forces => Q ===
+	Local maxi-/  minima
+	Points of disconuity in Q
+	x=0.0 m   Q=-0.01 N
+	x=1.0 m   Q=5.995000000000084 N
+	x=2.0 m   Q=-1.0099999999998097 N
+	x=3.0 m   Q=4.990000000000296 N
+	x=3.9999999999996705 m   Q=-0.009999999999619792 N
+	Zero points in Q
+	x=0.9980000000000008 m
+	x=1.9989999999998906 m
+	x=2.9989999999997807 m
+	x=3.9979999999996707 m
+
+	=== Bending moment => M ===
+	Local maxi-/  minima
+	x=0.0 m   M=0.0 Nm
+	x=0.9980000000000008 m   M=-2.5049725149999653 Nm
+	x=1.9989999999998906 m   M=0.9970029950001726 Nm
+	x=2.9989999999997807 m   M=-2.5269875049995836 Nm
+	x=3.9979999999996707 m   M=-0.018966014999237325 Nm
+	Points of disconuity in M
+	x=0.9990000000000008 m   M=-2.488004504999965 Nm
+	x=1.9999999999998905 m   M=0.991985000000173 Nm
+	x=2.9999999999997806 m   M=-2.4890234999995826 Nm
+	Zero points in M
+	x=0.0 m
+	x=1.5339999999999419 m
+	x=2.4569999999998404 m
+	x=3.9999999999996705 m
+
+	=== Normal forces => N ===
+	x=2.0 m   N[N]=0.0 NBeam Calc
 
 
 ![](LeadingSigns.png)