Question: how to solve for_loops_two with only one line of change?

[wh5a]

Usually the koans can be solved by only changing the marked line. I cannot figure out how to conditionally append a space except after the last element of the array. In the for loop, how do we know we've reached the end, without keeping a counter, or refactoring the code? Thanks!

[janek37]

Yes, this koan is broken, but this project is dead.

[ghost]

Not sure if you consider this one line but it's one statement:

sentence = if sentence.is_empty() {
    word.to_string()
} else {
    sentence + " " + word
};

[kenaniah]

If you don't mind refactoring the koan, you could reduce it to the following:

let sentence: String = words.join(" ");

I'm unaware of a solution that would be a one-line expression inside of the loop

[benash]

Here's what I did:

sentence = (sentence + " " + word).trim().to_string();

[benmosher]

my normal tack in a loop (when there is no .join(" ") in the platform):

if !sentence.is_empty() { sentence += " " }
sentence += *word;

(no idea how many more semicolons are due here -- also learning for the first time today! and glad to have this resource even if it has a few rough edges)