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Currently, the query language has log base e, "Foo=log(Bar)", but not log base 10 support. SQL has a LOG10 method, and java has java.lang.Math#log10.
e
"Foo=log(Bar)"
java.lang.Math#log10
Part of #3473
The text was updated successfully, but these errors were encountered:
In the meantime, users can workaround this with "Foo=log(Bar)/log(10)" (won't be as fast nor accurate though).
"Foo=log(Bar)/log(10)"
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devinrsmith
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Currently, the query language has log base
e
,"Foo=log(Bar)"
, but not log base 10 support. SQL has a LOG10 method, and java hasjava.lang.Math#log10
.Part of #3473
The text was updated successfully, but these errors were encountered: