The complement of an integer is the integer you get when you flip all the 0
's to 1
's and all the 1
's to 0
's in its binary representation.
- For example, The integer
5
is"101"
in binary and its complement is"010"
which is the integer2
.
Given an integer n
, return its complement.
Example 1:
Input: n = 5 Output: 2 Explanation: 5 is "101" in binary, with complement "010" in binary, which is 2 in base-10.
Example 2:
Input: n = 7 Output: 0 Explanation: 7 is "111" in binary, with complement "000" in binary, which is 0 in base-10.
Example 3:
Input: n = 10 Output: 5 Explanation: 10 is "1010" in binary, with complement "0101" in binary, which is 5 in base-10.
Constraints:
0 <= n < 109
Note: This question is the same as 476: https://leetcode.com/problems/number-complement/
class Solution:
def bitwiseComplement(self, n: int) -> int:
if n == 0:
return 1
ans = 0
find = False
for i in range(30, -1, -1):
b = n & (1 << i)
if not find and b == 0:
continue
find = True
if b == 0:
ans |= 1 << i
return ans
class Solution {
public int bitwiseComplement(int n) {
if (n == 0) {
return 1;
}
int ans = 0;
boolean find = false;
for (int i = 30; i >= 0; --i) {
int b = n & (1 << i);
if (!find && b == 0) {
continue;
}
find = true;
if (b == 0) {
ans |= (1 << i);
}
}
return ans;
}
}
class Solution {
public:
int bitwiseComplement(int n) {
if (n == 0) return 1;
int ans = 0;
bool find = false;
for (int i = 30; i >= 0; --i) {
int b = n & (1 << i);
if (!find && b == 0) continue;
find = true;
if (b == 0) ans |= (1 << i);
}
return ans;
}
};
func bitwiseComplement(n int) int {
if n == 0 {
return 1
}
ans := 0
find := false
for i := 30; i >= 0; i-- {
b := n & (1 << i)
if !find && b == 0 {
continue
}
find = true
if b == 0 {
ans |= (1 << i)
}
}
return ans
}