README_EN.md

1913. Maximum Product Difference Between Two Pairs

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Description

The product difference between two pairs (a, b) and (c, d) is defined as (a * b) - (c * d).

<li>For example, the product difference between <code>(5, 6)</code> and <code>(2, 7)</code> is <code>(5 * 6) - (2 * 7) = 16</code>.</li>

Given an integer array nums, choose four distinct indices w, x, y, and z such that the product difference between pairs (nums[w], nums[x]) and (nums[y], nums[z]) is maximized.

Return the maximum such product difference.

 

Example 1:

Input: nums = [5,6,2,7,4]

Output: 34

Explanation: We can choose indices 1 and 3 for the first pair (6, 7) and indices 2 and 4 for the second pair (2, 4).

The product difference is (6 * 7) - (2 * 4) = 34.

Example 2:

Input: nums = [4,2,5,9,7,4,8]

Output: 64

Explanation: We can choose indices 3 and 6 for the first pair (9, 8) and indices 1 and 5 for the second pair (2, 4).

The product difference is (9 * 8) - (2 * 4) = 64.

 

Constraints:

<li><code>4 &lt;= nums.length &lt;= 10<sup>4</sup></code></li>

<li><code>1 &lt;= nums[i] &lt;= 10<sup>4</sup></code></li>

Solutions

Solution 1

class Solution:
    def maxProductDifference(self, nums: List[int]) -> int:
        nums.sort()
        return nums[-1] * nums[-2] - nums[0] * nums[1]

class Solution {
    public int maxProductDifference(int[] nums) {
        Arrays.sort(nums);
        int n = nums.length;
        return nums[n - 1] * nums[n - 2] - nums[0] * nums[1];
    }
}

class Solution {
public:
    int maxProductDifference(vector<int>& nums) {
        sort(nums.begin(), nums.end());
        int n = nums.size();
        return nums[n - 1] * nums[n - 2] - nums[0] * nums[1];
    }
};

func maxProductDifference(nums []int) int {
	sort.Ints(nums)
	n := len(nums)
	return nums[n-1]*nums[n-2] - nums[0]*nums[1]
}

/**
 * @param {number[]} nums
 * @return {number}
 */
var maxProductDifference = function (nums) {
    nums.sort((a, b) => a - b);
    let n = nums.length;
    let ans = nums[n - 1] * nums[n - 2] - nums[0] * nums[1];
    return ans;
};