README_EN.md

1915. Number of Wonderful Substrings

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Description

A wonderful string is a string where at most one letter appears an odd number of times.

<li>For example, <code>&quot;ccjjc&quot;</code> and <code>&quot;abab&quot;</code> are wonderful, but <code>&quot;ab&quot;</code> is not.</li>

Given a string word that consists of the first ten lowercase English letters ('a' through 'j'), return the number of wonderful non-empty substrings in word. If the same substring appears multiple times in word, then count each occurrence separately.

A substring is a contiguous sequence of characters in a string.

 

Example 1:

Input: word = "aba"

Output: 4

Explanation: The four wonderful substrings are underlined below:

- "aba" -> "a"

- "aba" -> "b"

- "aba" -> "a"

- "aba" -> "aba"

Example 2:

Input: word = "aabb"

Output: 9

Explanation: The nine wonderful substrings are underlined below:

- "aabb" -> "a"

- "aabb" -> "aa"

- "aabb" -> "aab"

- "aabb" -> "aabb"

- "aabb" -> "a"

- "aabb" -> "abb"

- "aabb" -> "b"

- "aabb" -> "bb"

- "aabb" -> "b"

Example 3:

Input: word = "he"

Output: 2

Explanation: The two wonderful substrings are underlined below:

- "he" -> "h"

- "he" -> "e"

 

Constraints:

<li><code>1 &lt;= word.length &lt;= 10<sup>5</sup></code></li>

<li><code>word</code> consists of lowercase English letters from <code>&#39;a&#39;</code>&nbsp;to <code>&#39;j&#39;</code>.</li>

Solutions

Solution 1

class Solution:
    def wonderfulSubstrings(self, word: str) -> int:
        cnt = Counter({0: 1})
        ans = st = 0
        for c in word:
            st ^= 1 << (ord(c) - ord("a"))
            ans += cnt[st]
            for i in range(10):
                ans += cnt[st ^ (1 << i)]
            cnt[st] += 1
        return ans

class Solution {
    public long wonderfulSubstrings(String word) {
        int[] cnt = new int[1 << 10];
        cnt[0] = 1;
        long ans = 0;
        int st = 0;
        for (char c : word.toCharArray()) {
            st ^= 1 << (c - 'a');
            ans += cnt[st];
            for (int i = 0; i < 10; ++i) {
                ans += cnt[st ^ (1 << i)];
            }
            ++cnt[st];
        }
        return ans;
    }
}

class Solution {
public:
    long long wonderfulSubstrings(string word) {
        int cnt[1024] = {1};
        long long ans = 0;
        int st = 0;
        for (char c : word) {
            st ^= 1 << (c - 'a');
            ans += cnt[st];
            for (int i = 0; i < 10; ++i) {
                ans += cnt[st ^ (1 << i)];
            }
            ++cnt[st];
        }
        return ans;
    }
};

func wonderfulSubstrings(word string) (ans int64) {
	cnt := [1024]int{1}
	st := 0
	for _, c := range word {
		st ^= 1 << (c - 'a')
		ans += int64(cnt[st])
		for i := 0; i < 10; i++ {
			ans += int64(cnt[st^(1<<i)])
		}
		cnt[st]++
	}
	return
}

function wonderfulSubstrings(word: string): number {
    const cnt: number[] = new Array(1 << 10).fill(0);
    cnt[0] = 1;
    let ans = 0;
    let st = 0;
    for (const c of word) {
        st ^= 1 << (c.charCodeAt(0) - 'a'.charCodeAt(0));
        ans += cnt[st];
        for (let i = 0; i < 10; ++i) {
            ans += cnt[st ^ (1 << i)];
        }
        cnt[st]++;
    }
    return ans;
}

/**
 * @param {string} word
 * @return {number}
 */
var wonderfulSubstrings = function (word) {
    const cnt = new Array(1024).fill(0);
    cnt[0] = 1;
    let ans = 0;
    let st = 0;
    for (const c of word) {
        st ^= 1 << (c.charCodeAt() - 'a'.charCodeAt());
        ans += cnt[st];
        for (let i = 0; i < 10; ++i) {
            ans += cnt[st ^ (1 << i)];
        }
        cnt[st]++;
    }
    return ans;
};