lambda expression with 'out' keyword omitting type

[goyzhang]

If we define out parameter in a lambda, we have to explicitly define the type like:

           delegate int D<TResult, TArgument>(TArgument argument,  out TResult result);
            D<int, int> d = (int arg, out int rst) => {...};  //have to claim int
            //D<int, int> d = (arg, out rst) => {...};  //CS2046

Can we get rid of int (the type define) for out and do the similar thing like the case without out?

           delegate int D<TResult, TArgument>(TArgument argument,  TResult result);
            D<int, int> d = (arg, rst) => {...};  // without `out`, you can just omit `int`

[Thaina]

We already have out var result

[goyzhang]

We already have out var result

Yes, I know, but it 's not the case I talked about. And it doesn't work with lambda

[svick]

This looks like a duplicate of #338.

[YairHalberstadt]

Closing as championed at #338