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The a & b operator requires a lot of magic to work and some things are strictly impossible to detect (e.g. (a & b) & c is length 3 instead of length 2, while x = a & b; x & c is length 2). There should at least be the option to parse a sequence of tokens without using the magic operator, just like longest exists as an alternative to a | b.
The text was updated successfully, but these errors were encountered:
The
a & b
operator requires a lot of magic to work and some things are strictly impossible to detect (e.g.(a & b) & c
is length 3 instead of length 2, whilex = a & b; x & c
is length 2). There should at least be the option to parse a sequence of tokens without using the magic operator, just likelongest
exists as an alternative toa | b
.The text was updated successfully, but these errors were encountered: