-
Notifications
You must be signed in to change notification settings - Fork 0
/
0119.go
47 lines (42 loc) · 1.11 KB
/
0119.go
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
// Source: https://leetcode.com/problems/pascals-triangle-ii
// Title: Pascal's Triangle II
// Difficulty: Easy
// Author: Mu Yang <http://muyang.pro>
////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
// Given an integer rowIndex, return the rowIndexth (0-indexed) row of the Pascal's triangle.
//
// In Pascal's triangle, each number is the sum of the two numbers directly above it as shown:
//
// https://upload.wikimedia.org/wikipedia/commons/0/0d/PascalTriangleAnimated2.gif
//
// Example 1:
//
// Input: rowIndex = 3
// Output: [1,3,3,1]
//
// Example 2:
//
// Input: rowIndex = 0
// Output: [1]
//
// Example 3:
//
// Input: rowIndex = 1
// Output: [1,1]
//
// Constraints:
//
// 0 <= numRows <= 33
//
////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
package main
func getRow(rowIndex int) []int {
row := make([]int, rowIndex+1)
for i := 0; i <= rowIndex; i++ {
row[i] = 1
for j := i - 1; j > 0; j-- {
row[j] += row[j-1]
}
}
return row
}