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open link in browser and return to app #20217
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We are automatically closing this issue because it does not appear to follow any of the provided issue templates. Please make use of the bug report template to let us know about a reproducible bug or regression in the core React Native library. If you'd like to start a discussion, check out https://discuss.reactjs.org or follow the discussion template. |
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Jul 16, 2018
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Resolution: Locked
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I've developing an app in react-native that should communicate with a gateway for payments, after finishing the payment process (success or failure) I need to show an alert to user. For this purpose, I open a link in
WebView
and after that I get return's url withonNavigationStateChange
and show success or failure message.But, this flow for security issues must be done in a default device browser.
Current Code:
Any idea?
Thanks
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