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FirstMissingPositive41.java
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/**
* Given an unsorted integer array, find the first missing positive integer.
*
* For example,
* Given [1,2,0] return 3,
* and [3,4,-1,1] return 2.
*
* Your algorithm should run in O(n) time and uses constant space.
*/
import java.util.ArrayList;
import java.util.List;
public class FirstMissingPositive41 {
public int firstMissingPositive(int[] nums) {
List<Boolean> isMissing = new ArrayList<>();
isMissing.add(false);
int firstMissing = 1;
for (int i = 0; i < nums.length; i++) {
int now = nums[i];
if (now > 0) {
try {
if (isMissing.get(now)) {
isMissing.set(now, false);
}
} catch (IndexOutOfBoundsException e) {
while (isMissing.size() < now) {
isMissing.add(true);
}
isMissing.add(false);
}
}
try {
while (!isMissing.get(firstMissing)) {
firstMissing++;
}
} catch (IndexOutOfBoundsException e) {
isMissing.add(true);
}
}
return firstMissing;
}
/**
*
*/
public int firstMissingPositive2(int[] nums) {
if (nums == null || nums.length == 0) {
return 1;
}
for (int i = 0; i < nums.length; ++i) {
while (nums[i] > 0 && nums[i] <= nums.length && nums[i] - 1 != i) {
int tmp = nums[nums[i] - 1];
if (tmp == nums[i]) {
break;
}
nums[nums[i] - 1] = nums[i];
nums[i] = tmp;
}
}
for (int i = 0; i < nums.length; ++i) {
if (nums[i] != i + 1) {
return i + 1;
}
}
return nums.length + 1;
}
/**
* https://leetcode.com/problems/first-missing-positive/discuss/17083/O(1)-space-Java-Solution
*/
public int firstMissingPositive3(int[] A) {
int i = 0;
while(i < A.length){
if(A[i] == i+1 || A[i] <= 0 || A[i] > A.length) i++;
else if (A[A[i]-1] != A[i]) swap(A, i, A[i]-1);
else i++;
}
i = 0;
while(i < A.length && A[i] == i+1) i++;
return i+1;
}
private void swap(int[] A, int i, int j){
int temp = A[i];
A[i] = A[j];
A[j] = temp;
}
public int firstMissingPositive4(int[] nums) {
if (nums == null || nums.length == 0) return 1;
int N = nums.length;
for (int i=0; i<N; i++) {
int idx = i;
int val = nums[idx];
while (idx >= 0 && idx < N && val > 0 && val <= N && nums[idx] != idx + 1) {
int newVal = nums[val - 1];
nums[val - 1] = val;
idx = newVal - 1;
val = newVal;
}
}
for (int i=0; i<N; i++) {
if (nums[i] != i + 1) {
return i + 1;
}
}
return N + 1;
}
}