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NumberOfLongestIncreasingSubsequence673.java
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/**
* Given an unsorted array of integers, find the number of longest increasing
* subsequence.
*
* Example 1:
* Input: [1,3,5,4,7]
* Output: 2
* Explanation: The two longest increasing subsequence are
* [1, 3, 4, 7] and [1, 3, 5, 7].
*
* Example 2:
* Input: [2,2,2,2,2]
* Output: 5
* Explanation: The length of longest continuous increasing subsequence is 1,
* and there are 5 subsequences' length is 1, so output 5.
*
* Note: Length of the given array will be not exceed 2000 and the answer is
* guaranteed to be fit in 32-bit signed int.
*/
public class NumberOfLongestIncreasingSubsequence673 {
public int findNumberOfLIS(int[] nums) {
if (nums == null || nums.length == 0) return 0;
int N = nums.length;
int[] dp = new int[N];
int[] count = new int[N];
int res = 0;
int maxLen = 1;
for (int i=0; i<N; i++) {
int curr = nums[i];
int localRes = 1;
int localCount = 1;
for (int j=0; j<i; j++) {
if (curr > nums[j]) {
if (dp[j] + 1 > localRes) {
localRes = dp[j] + 1;
localCount = count[j];
} else if (dp[j] + 1 == localRes) {
localCount += count[j];
}
}
}
if (localRes > maxLen) {
maxLen = localRes;
res = localCount;
} else if (localRes == maxLen) {
res += localCount;
}
count[i] = localCount;
dp[i] = localRes;
}
return res;
}
}