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PathSum112.java
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/**
* Given a binary tree and a sum, determine if the tree has a root-to-leaf path
* such that adding up all the values along the path equals the given sum.
*
* For example:
* Given the below binary tree and sum = 22,
* 5
* / \
* 4 8
* / / \
* 11 13 4
* / \ \
* 7 2 1
* return true, as there exist a root-to-leaf path 5->4->11->2 which sum is 22.
*/
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class PathSum112 {
public boolean hasPathSum(TreeNode root, int sum) {
return sum(root, sum, 0);
}
private boolean sum(TreeNode root, int sum, int sumForNow) {
if (root == null) {
return false;
}
sumForNow += root.val;
if (sumForNow == sum && root.left == null && root.right == null) {
return true;
}
if (sum(root.left, sum, sumForNow)) {
return true;
}
return sum(root.right, sum, sumForNow);
}
/**
* https://discuss.leetcode.com/topic/3149/accepted-my-recursive-solution-in-java
*/
public boolean hasPathSum2(TreeNode root, int sum) {
if(root == null) return false;
if(root.left == null && root.right == null && sum - root.val == 0) return true;
return hasPathSum(root.left, sum - root.val) || hasPathSum(root.right, sum - root.val);
}
}